[Solved] Javascript Classwork 5

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1. Write a function to get the most common character in the string (use function composition).
2. We have an array, filter the even numbers from the array. Then, calculate a sum of all the remaining numbers, and after that print sum of numbers in this format `The result is ${result}.` (use function composition).
3. Create a function that takes a list of functions and sorts them in ascending order based on how many calls are needed for them to return a non-function.f1 = _ => hello // f1() hellof2 = _ => _ => world // f2()() worldf3 = _ => _ => _ => user // f3()()() userfuncSort([f2, f3, f1]) [f1, f2, f3]// [f2, f3, f1] [2, 3, 1] [1, 2, 3] [f1, f2, f3]funcSort([f1, f2, f3]) [f1, f2, f3]// [f1, f2, f3] [1, 2, 3] [1, 2, 3] [f1, f2, f3]funcSort([f2, func]) [func, f2]// [f2, func] [2, 0] [0, 2] [func, f2]
4. Create a function that groups an array of numbers based on a size parameter. The size represents the maximum length of each sub-array.

      [1, 2, 3, 4, 5, 6], 3   [[1, 3, 5], [2, 4, 6]]   // Divide array into groups of size 3.

      [1, 2, 3, 4, 5, 6], 2   [[1, 4], [2, 5], [3, 6]]   // Divide array into groups of size 2.

      [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11], 4   [[1, 4, 7, 10], [2, 5, 8, 11], [3, 6, 9]]   // "Leftover" arrays are okay.

   group([1, 2, 3, 4], 2) [[1, 3], [2, 4]]group([1, 2, 3, 4, 5, 6, 7], 4) [[1, 3, 5, 7], [2, 4, 6]]

group([1, 2, 3, 4, 5], 1) [[1], [2], [3], [4], [5]] group([1, 2, 3, 4, 5, 6], 4) [[1, 3, 5], [2, 4, 6]]

The size parameter represents the maximum size for each sub-array (see ex.4).You should try to fill each sub-array evenly. In other words, ex.4 should be [[1, 3, 5], [2, 4, 6]], not [[1, 3, 5, 6], [2, 4]].

Keep the relative order of the numbers in each sub-array the same as the order in the original array.

5. Write Pagination object that will get an array and pageSize, then will return the following. nextPage prevPage firstPage lastPage goToPage getPageItemsconst alphabetArray = abcdefghijklmnopqrstuvwxyz.split(); Pagination.init(alphabetArray, 4);Pagination.getPageItems(); // [a, b, c, d] Pagination.nextPage(); // add the current page by onePagination.getPageItems(); // [e, f, g, h] Pagination.nextPage().nextPage(); // the ability to call chainable Pagination.goToPage(3); // current page must be set to 3
6. Write an Airplane object that initializes name.Give airplanes the ability to .takeOff() and .land():

• If a plane lands, its isFlying property is set to false.
• If a plane takes off, its isFlying property is set to true.

7. Your task is to create a Circle constructor function that creates a circle with a radius provided by an argument. The circles constructed must have two methods getArea() (PIr^2) and getPerimeter() (2PI*r) which give both respective areas and perimeter (circumference).let circy = new Circle(11); circy.getArea();// Should return 380.132711084365let circy = new Circle(4.44); circy.getPerimeter();// Should return 27.897342763877365
8. Create a gather function that accepts a string argument and returns another function. The function calls should support continued chaining until the order is called.The order should accept a number as an argument and return another function. The function calls should support continued chaining until the get iscalled.get should return all of the arguments provided to the gather functions as a string in the order specified in the order functions.gather(a)(b)(c).order(0)(1)(2).get() abc gather(a)(b)(c).order(2)(1)(0).get() cbagather(e)(l)(o)(l)(!)(h).order(5)(0)(1)(3)(2)(4).get() hello!Expect to gather and order to chain any number of times, but always with the same number of invocations for each (i.e both functions will always be chained the same number of times).
9. A complete bracelet is an array with at least one subsequence (pattern) repeating at least two times, and completely the subsequence cannot be cut-off at any point. The subsequence must have a length two or greater.

   [1, 2, 3, 3, 1, 2, 3, 3]  // Pattern: [1, 2, 3, 3]   [1, 2, 1, 2, 1, 2, 1, 2]  // Pattern: [1, 2] or [1, 2, 1, 2]

   [1, 1, 6, 1, 1, 7, 1, 1, 6, 1, 1, 7, 1, 1, 6, 1, 1, 7]  // Pattern:   [1, 1, 6, 1, 1, 7]

   [4, 4, 3, 4, 4, 4, 4, 3, 4, 4]  // Pattern: [4, 4, 3, 4, 4]

Incomplete bracelets:

   [1, 2, 2, 2, 1, 2, 2, 2, 1]  // Incomplete (chopped off)   [1, 1, 6, 1, 1, 7]  // Incomplete (subsequence repeats only once)

Create a function that returns true if a bracelet is complete, and false otherwise.

completeBracelet([1, 2, 2, 1, 2, 2]) true completeBracelet([5, 1, 2, 2]) false

completeBracelet([5, 5, 5]) false// potential pattern [5, 5] cut-off (patterns >= 2)

Patterns must be at least two integers in length.

10. Create a function that takes an array of students and returns an object representing their notes distribution. Have in mind that all invalid notes should not be count in the distribution. Valid notes are: 1, 2, 3, 4, 5

getNotesDistribution([ {

name: Steve,

notes: [5, 5, 3, -1, 6] },

{name: John, notes: [3, 2, 5, 0, -3]

}

]{ 5: 3, 3: 2,

2: 1 })

11. Create a function that recursively counts the integers number of digits. count(318) 3count(-92563) 5count(4666) 4

count(-314890) 6 count(654321) 6

12. Write recursive a function that, given the start startNum and end endNum values, return an array containing all the numbers inclusive to that range. See examples below.

inclusiveArray(1, 5) [1, 2, 3, 4, 5] inclusiveArray(2, 8) [2, 3, 4, 5, 6, 7, 8]

inclusiveArray(10, 20) [10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]