[Solved] EECE 1080 Lab3- I Feel Loopy

The objective of this assignment is to practice using loops. You will create several short programming assignments to get more familiar with C/C++ looping concepts.

Loop 1:

Write a for loop that displays the sum and floating point average of values from 2 up to and including 35 with loop interval (step count) of 3

Output:

SUM: 222

AVERAGE: 18.5

Loop 2:

Use filename: loopset2.cpp

Modify Loop 1 to take parameters for loop starting index, ending index, and loop interval (step count). Again output the average and sum.

Example 1:

For the following input values:

Starting index: 0

Ending Index 10

Step count: 5

SUM: 15

AVERAGE: 5

Example 2:

For the following input values:

Starting index: 3

Ending Index 10

Step count: 1

SUM: 52

AVERAGE: 6.5

Loop 3:

Use filename: loopset3.cpp

Write a for loop that goes from a provided starting point to 0 in loop steps of 0.5

Example Output 1:

Starting Point of 25

25,24.5,24,23.5,,0 Note: No trailing comma in output

Part B: Loopset 2 practice

Use filename: dataentry.cpp

Write a Do While loop that allows the user to enter floating point numbers greater than 0 and sums these numbers and prints the sum after the loop. The loop should exit after a number less than or equal to 0 is entered.

Please do not add in values less than or equal to zero.

Sample Output #1:

Enter Positive Number to Add or Enter Zero or Negative Number to End: 99.0

Enter Positive Number to Add or Enter Zero or Negative Number to End: 67.5

Enter Positive Number to Add or Enter Zero or Negative Number to End: 0

Sum of Entered Numbers: 166.5

Sample Output #2:

Enter Positive Number to Add or Enter Zero or Negative Number to End: -1

Sum of Entered Numbers: 0

Part C: Picture making

1. Create a loop to display a solidly filled rectangle of width, and height. Use an * as a fill character

Use filename: solidrect.cpp

Sample 1: Even Height and Width

Width?50

Height?12

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Sample 2: Odd Height and Width

Width?25

Height?3

*************************

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1. Create a loop to display a framed rectangle of width, and height. Use a fill character of *.

Use filename: framedrect.cpp

Sample 1:

Width?8

Height?5

********

* *

* *

* *

********

Sample 2:

Width?50

Height?10

**************************************************

* *

* *

* *

* *

* *

* *

* *

* *

**************************************************

Part D: Object height over time with a specific initial velocity.

Use filename: projectile.cpp

Write a program that creates a table that shows the height of a object launched straight up for each second from launch time (time zero) until the object reaches the ground (height less than or equal to zero). The height after t seconds is given by:

s = V₀t (g)(t²)

Where:

• V₀ is the initial velocity in m/s
• g is the gravitational constant and has a value of 9.8 m/s²
• t is the current time in seconds

The program should prompt the user for the launch velocity.

The program should generate a table that looks something like the following:

Enter Initial V0: 60

Initial Velocity of Object: 60-m/s

Time Height

0 0

1 55.1

2 100.4

3 135.9

4 161.6

5 177.5

6 183.6

7 179.9

8 166.4

9 143.1

10 110

11 67.1

12 14.4

13 0

Total Time: 13-seconds

Maximum Height: 183.6 @ 6-seconds

Part E: Metal Expansion Table

Use filename: metalexp.cpp

In this section, you will create a table of metal expansion versus temperature. You will determine if the metal expansion is within a certain tolerance.

The fact that most metals expand when heated and contract when cooled has implications when the laboratory equipment involved. The size for typical aluminum bar that is w cm wide at 70-degrees fahrenheit can found using the following:

x = w + (t 70)(0.0001)

at the specified temperature of t. Write a program that prompts the user for the standard width of the bar and the tolerance (plus or minus the standard bar width). Display a table to the screen from a temperature of 60 to 85F in one-degree intervals marking with a star the temperatures which lay within the tolerance.

You will need to use the iomanip library to format the output of this code. Here is a short example:

#include <iomanip> // add to top

double x = 999.999;

cout << fixed << setw(11) << setprecision(7) << x << endl;

Will display 999.9990000

Sample Output:

Width: 10

Tolerance: .00050

Temperature Width Within Tolerance

60 9.9990000

61 9.9991000

62 9.9992000

63 9.9993000

64 9.9994000

65 9.9995000

66 9.9996000 *

67 9.9997000 *

68 9.9998000 *

69 9.9999000 *

70 10.0000000 *

71 10.0001000 *

72 10.0002000 *

73 10.0003000 *

74 10.0004000 *

75 10.0005000

76 10.0006000

77 10.0007000

78 10.0008000

79 10.0009000

80 10.0010000

81 10.0011000

82 10.0012000

83 10.0013000

84 10.0014000

85 10.0015000

Part F: Writing a loop to calculate a factorial

Use filename: factorial.cpp

No cin/cout statements should be added to the function.

In this part we introducing you to a function body for the first time. Just follow the comments in the provided template and should be good to go.

The factorial of a number is the result of multiplying a sequence of numbers (such as 4 x 3 x 2 x 1 is 4 factorial). A factorial of number is indicated using the exclamation point so for the example above the short hand would be 4!.

Note: the factorial of one and zero are both one.

We are going to create a loop inside a function called factorial(). Calculate the factorial using a for loop. Make sure your function works with the numbers for zero and one as well. Verify the test case output before submitting.

Part G: Create the solution to calculate e^x

Use filename: exp.cpp

No cin/cout statements should be added to the function.

Note: The exp(5) is incorrectly stated as 120 in the test code for this lab. Please replace 120 with the correct value for testing.

The Natural Exponential Function e^x can be found using the following mathematical expression.

e^x = 1 + x¹/1! + x²/2! + x³/3! + .

Your task is convert this expression into C++ code using your previously defined factorial function and a loop. You should calculate at least the first 15-20 terms of this expression. Just make sure that the solution has converged (ie. abs(previously_calculated_e currently_calculated_e) < 0.0001).

You will embed the necessary loop and other logic in the provided template.