Problem 1.
Let
x ai T(x) = ai+1 ai
with x [ai,ai+1). T : J J where J = [0,1). And 0 = a0 < a1 < < ak = 1. We want to show that T is a measure preserving transformation of (J,L(J),) regardless of choice of {ai}.
We have that T1(x) = x(ai+1ai)+ai. Let C be the collection of left-closed, right-open dyadic intervals in [0,1). We saw in Section 2.7 that C is a sufficient semi-ring. For I we write I = [k/2i,(k + 1)/2i) for integers k,i with i 0 and k {0,,2i 1}. Observe that (I) = 1/2i for all I C. Assume for a fixed I that I [ai,ai+1) for some i {0,k}.
Then,
!
1 k k + 1
T (I) = 2i(ai+1 ai) + ai, i (ai+1 ai) + ai
2
T1(I) is an interval for any I and is hence a measurable set. Moreover,
1 k + 1 k
(T (I)) = i (ai+1 ai) + ai ( i(ai+1 ai) + ai)
2 2
k + 1 k + 1 k k
= 2i ai+1 2i ai 2iai+1 + 2iai
(k + 1)(ai+1 ai) k(ai+1 ai)
=
2i
((k + 1) k)(ai+1 ai)
=
=
2i
Observe that T maps some values onto I for each T defined on the intervals [ai,ai+1). Hence, there will be k such intervals resulting from I with the same length as the above when applying T1.
1
If we add this up over all intervals [ai,ai+1), we get,
ak a0 1
= = (I) 2i 2i
as required. Hence, we can apply Theorem 3.4.1 in order to assert that T is then a measure-preserving transformation.
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