[Solved] CSC482 Homework8-SQL Injection

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SQL injection is a code injection technique that exploits the vulnerabilities in the interface between web applications and database servers. The vulnerability is present when users inputs are not correctly checked within the web applications before being sent to the back-end database servers.

Many web applications take inputs from users, and then use these inputs to construct SQL queries, so they can get information from the database. Web applications also use SQL queries to store information in the database. These are common practices in the development of web applications. When SQL queries are not carefully constructed, SQL injection vulnerabilities can occur. SQL injection is one of the most common attacks on web applications.

In this lab, we have created a web application that is vulnerable to the SQL injection attack. Our web application includes the common mistakes made by many web developers. Students goal is to find ways to exploit the SQL injection vulnerabilities, demonstrate the damage that can be achieved by the attack, and master the techniques that can help defend against such type of attacks. This lab covers the following topics:

  • SQL statement: SELECT and UPDATE statements
  • SQL injection
  • Prepared statement

Readings. Detailed coverage of the SQL injection can be found in the following:

  • Chapter 12 of the SEED Book, Computer & Internet Security: A Hands-on Approach, 2nd Edition, by Wenliang Du. See details at https://www.handsonsecurity.net.

Lab Environment. This lab has been tested on our pre-built Ubuntu 16.04 VM, which can be downloaded from the SEED website.

1 Lab Environment

We have developed a web application for this lab. The folder where the application is installed and the URL to access this web application are described in the following:

URL: http://www.SEEDLabSQLInjection.com Folder: /var/www/SQLInjection/

The above URL is is only accessible from inside of the virtual machine, because we have modified the /etc/hosts file to map the domain name of each URL to the virtual machines local IP address (127.0.0.1). You may map any domain name to a particular IP address using /etc/hosts. For example, you can map http://www.example.com to the local IP address by appending the following entry to /etc/hosts:

127.0.0.1 www.example.com

If your web server and browser are running on two different machines, you need to modify /etc/hosts on the browsers machine accordingly to map these domain names to the web servers IP address, not to 127.0.0.1.

Apache Configuration. In our pre-built VM image, we used Apache server to host all the web sites used in the lab. The name-based virtual hosting feature in Apache could be used to host several web sites (or URLs) on the same machine. A configuration file named 000-default.conf in the directory /etc/ apache2/sites-available contains the necessary directives for the configuration:

Inside the configuration file, each web site has a VirtualHost block that specifies the URL for the web site and directory in the file system that contains the sources for the web site. The following examples show how to configure a website with URL http://www.example1.com and another website with URL http://www.example2.com:

<VirtualHost *>ServerName http://www.example1.comDocumentRoot /var/www/Example_1/</VirtualHost><VirtualHost *>ServerName http://www.example2.comDocumentRoot /var/www/Example_2/</VirtualHost>

You may modify the web application by accessing the source in the mentioned directories. For example, with the above configuration, the web application http://www.example1.com can be changed by modifying the sources in the /var/www/Example_1/ directory. After a change is made to the configuration, the Apache server needs to be restarted. See the following command:

$ sudo service apache2 start

2 Lab Tasks

We have created a web application, and host it at www.SEEDLabSQLInjection.com. This web application is a simple employee management application. Employees can view and update their personal information in the database through this web application. There are mainly two roles in this web application: Administrator is a privilege role and can manage each individual employees profile information; Employee is a normal role and can view or update his/her own profile information. All employee information is described in the following table.

Name Employee ID Password Salary Birthday SSN Nickname Email Address Phone#
Admin 99999 seedadmin 400000 3/5 43254314
Alice 10000 seedalice 20000 9/20 10211002
Boby 20000 seedboby 50000 4/20 10213352
Ryan 30000 seedryan 90000 4/10 32193525
Samy 40000 seedsamy 40000 1/11 32111111
Ted 50000 seedted 110000 11/3 24343244

2.1 Task 1: Get Familiar with SQL Statements

The objective of this task is to get familiar with SQL commands by playing with the provided database. We have created a database called Users, which contains a table called credential; the table stores the personal information (e.g. eid, password, salary, ssn, etc.) of every employee. In this task, you need to play with the database to get familiar with SQL queries.

MySQL is an open-source relational database management system. We have already setup MySQL in our SEEDUbuntu VM image. The user name is root and password is seedubuntu. Please login to MySQL console using the following command:

$ mysql -u root -pseedubuntu

After login, you can create new database or load an existing one. As we have already created the Users database for you, you just need to load this existing database using the following command:

mysql> use Users;

To show what tables are there in the Users database, you can use the following command to print out all the tables of the selected database.

mysql> show tables;

After running the commands above, you need to use a SQL command to print all the profile information of the employee Alice. Please provide the screenshot of your results.

2.2 Task 2: SQL Injection Attack on SELECT Statement

SQL injection is basically a technique through which attackers can execute their own malicious SQL statements generally referred as malicious payload. Through the malicious SQL statements, attackers can steal information from the victim database; even worse, they may be able to make changes to the database. Our employee management web application has SQL injection vulnerabilities, which mimic the mistakes frequently made by developers.

We will use the login page from www.SEEDLabSQLInjection.com for this task. The login page is shown in Figure 1. It asks users to provide a user name and a password. The web application authenticate users based on these two pieces of data, so only employees who know their passwords are allowed to log in. Your job, as an attacker, is to log into the web application without knowing any employees credential.

To help you started with this task, we explain how authentication is implemented in the web application.

The PHP code unsafehome.php, located in the /var/www/SQLInjection directory, is used to conduct user authentication. The following code snippet show how users are authenticated.

$input_uname = $_GET[username];$input_pwd = $_GET[Password]; $hashed_pwd = sha1($input_pwd); $sql = SELECT id, name, eid, salary, birth, ssn, address, email, nickname, PasswordFROM credentialWHERE name= $input_uname and Password=$hashed_pwd;$result = $conn -> query($sql);// The following is Pseudo Code if(id != NULL) {

Figure 1: The Login page

if(name==admin) { return All employees information;} else if (name !=NULL){ return employee information; }} else {Authentication Fails;}

The above SQL statement selects personal employee information such as id, name, salary, ssn etc from the credential table. The SQL statement uses two variables inputuname and hashedpwd, where inputuname holds the string typed by users in the username field of the login page, while hashedpwd holds the sha1 hash of the password typed by the user. The program checks whether any record matches with the provided username and password; if there is a match, the user is successfully authenticated, and is given the corresponding employee information. If there is no match, the authentication fails.

  • Task 2.1: SQL Injection Attack from webpage. Your task is to log into the web application as the administrator from the login page, so you can see the information of all the employees. We assume that you do know the administrators account name which is admin, but you do not the password. You need to decide what to type in the Username and Password fields to succeed in the attack.
  • Task 2.2: SQL Injection Attack from command line. Your task is to repeat Task 2.1, but you need to do it without using the webpage. You can use command line tools, such as curl, which can send HTTP requests. One thing that is worth mentioning is that if you want to include multiple parameters in HTTP requests, you need to put the URL and the parameters between a pair of single quotes; otherwise, the special characters used to separate parameters (such as &) will be interpreted by the shell program, changing the meaning of the command. The following example shows how to send an HTTP GET request to our web application, with two parameters (username and Password) attached:

$ curl

www.SeedLabSQLInjection.com/index.php?username=alice&Password=111

If you need to include special characters in the username or Password fields, you need to encode them properly, or they can change the meaning of your requests. If you want to include single quote in those fields, you should use %27 instead; if you want to include white space, you should use %20. In this task, you do need to handle HTTP encoding while sending requests using curl.

  • Task 2.3: Append a new SQL statement. In the above two attacks, we can only steal information from the database; it will be better if we can modify the database using the same vulnerability in the login page. An idea is to use the SQL injection attack to turn one SQL statement into two, with the second one being the update or delete statement. In SQL, semicolon (;) is used to separate two SQL statements. Please describe how you can use the login page to get the server run two SQL statements. Try the attack to delete a record from the database, and describe your observation.

2.3 Task 3: SQL Injection Attack on UPDATE Statement

If a SQL injection vulnerability happens to an UPDATE statement, the damage will be more severe, because attackers can use the vulnerability to modify databases. In our Employee Management application, there is an Edit Profile page (Figure 2) that allows employees to update their profile information, including nickname, email, address, phone number, and password. To go to this page, employees need to log in first.

When employees update their information through the Edit Profile page, the following SQL UPDATE query will be executed. The PHP code implemented in unsafeeditbackend.php file is used to update employees profile information. The PHP file is located in the /var/www/SQLInjection directory.

$hashed_pwd = sha1($input_pwd);$sql = UPDATE credential SET nickname=$input_nickname, email=$input_email, address=$input_address, Password=$hashed_pwd,PhoneNumber=$input_phonenumberWHERE ID=$id;;$conn->query($sql);
  • Task 3.1: Modify your own salary. As shown in the Edit Profile page, employees can only update their nicknames, emails, addresses, phone numbers, and passwords; they are not authorized to change their salaries. Assume that you (Alice) are a disgruntled employee, and your boss Boby did not increase your salary this year. You want to increase your own salary by exploiting the SQL injection vulnerability in the Edit-Profile page. Please demonstrate how you can achieve that. We assume that you do know that salaries are stored in a column called salary.
  • Task 3.2: Modify other people salary. After increasing your own salary, you decide to punish your boss Boby. You want to reduce his salary to 1 dollar. Please demonstrate how you can achieve that.
  • Task 3.3: Modify other people password. After changing Bobys salary, you are still disgruntled, so you want to change Bobys password to something that you know, and then you can log into his account and do further damage. Please demonstrate how you can achieve that. You need to demonstrate that you can successfully log into Bobys account using the new password. One thing worth

Figure 2: The Edit-Profile page

mentioning here is that the database stores the hash value of passwords instead of the plaintext password string. You can again look at the unsafeeditbackend.php code to see how password is being stored. It uses SHA1 hash function to generate the hash value of password.

To make sure your injection string does not contain any syntax error, you can test your injection string on MySQL console before launching the real attack on our web application.

2.4 Task 4: Countermeasure Prepared Statement

The fundamental problem of the SQL injection vulnerability is the failure to separate code from data. When constructing a SQL statement, the program (e.g. PHP program) knows which part is data and which part is code. Unfortunately, when the SQL statement is sent to the database, the boundary has disappeared; the boundaries that the SQL interpreter sees may be different from the original boundaries that was set by the developers. To solve this problem, it is important to ensure that the view of the boundaries are consistent in the server-side code and in the database. The most secure way is to use prepared statement.

To understand how prepared statement prevents SQL injection, we need to understand what happens when SQL server receives a query. The high-level workflow of how queries are executed is shown in Figure 3. In the compilation step, queries first go through the parsing and normalization phase, where a query is checked against the syntax and semantics. The next phase is the compilation phase where keywords (e.g. SELECT, FROM, UPDATE, etc.) are converted into a format understandable to machines. Basically, in this phase, query is interpreted. In the query optimization phase, the number of different plans are considered to execute the query, out of which the best optimized plan is chosen. The chosen plan is store in the cache, so whenever the next query comes in, it will be checked against the content in the cache; if its already present in the cache, the parsing, compilation and query optimization phases will be skipped. The compiled query is then passed to the execution phase where it is actually executed.

Prepared statement comes into the picture after the compilation but before the execution step. A prepared statement will go through the compilation step, and be turned into a pre-compiled query with empty placeholders for data. To run this pre-compiled query, data need to be provided, but these data will not go

Figure 3: Prepared Statement Workflow

through the compilation step; instead, they are plugged directly into the pre-compiled query, and are sent to the execution engine. Therefore, even if there is SQL code inside the data, without going through the compilation step, the code will be simply treated as part of data, without any special meaning. This is how prepared statement prevents SQL injection attacks.

Here is an example of how to write a prepared statement in PHP. We use a SELECT statment in the following example. We show how to use prepared statement to rewrite the code that is vulnerable to SQL injection attacks.

$sql = SELECT name, local, genderFROM USER_TABLEWHERE id = $id AND password =$pwd ;$result = $conn->query($sql))

The above code is vulnerable to SQL injection attacks. It can be rewritten to the following

$stmt = $conn->prepare(SELECT name, local, genderFROM USER_TABLEWHERE id = ? and password = ? );// Bind parameters to the query$stmt->bind_param(is, $id, $pwd);$stmt->execute();$stmt->bind_result($bind_name, $bind_local, $bind_gender);$stmt->fetch();

Using the prepared statement mechanism, we divide the process of sending a SQL statement to the database into two steps. The first step is to only send the code part, i.e., a SQL statement without the actual the data. This is the prepare step. As we can see from the above code snippet, the actual data are replaced by question marks (?). After this step, we then send the data to the database using bindparam(). The database will treat everything sent in this step only as data, not as code anymore. It binds the data to the corresponding question marks of the prepared statement. In the bindparam() method, the first argument is indicates the types of the parameters: i means that the data in $id has the integer type, and s means that the data in $pwd has the string type.

For this task, please use the prepared statement mechanism to fix the SQL injection vulnerabilities exploited by you in the previous tasks. Then, check whether you can still exploit the vulnerability or not.

3 Guidelines

Test SQL Injection String. In real-world applications, it may be hard to check whether your SQL injection attack contains any syntax error, because usually servers do not return this kind of error messages. To conduct your investigation, you can copy the SQL statement from php source code to the MySQL console. Assume you have the following SQL statement, and the injection string is or 1=1;#.

SELECT * from credential

WHERE name=$name and password=$pwd;

You can replace the value of $name with the injection string and test it using the MySQL console. This approach can help you to construct a syntax-error free injection string before launching the real injection attack.

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[Solved] CSC482 Homework8-SQL Injection
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