[SOLVED] CS计算机代考程序代写 // from: https://en.cppreference.com/w/cpp/language/aggregate_initialization

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// from: https://en.cppreference.com/w/cpp/language/aggregate_initialization

#include
#include
struct S {
int x;
struct Foo {
int i;
int j;
int a[3];
} b;
};

union U {
int a;
const char* b;
};

int main()
{
S s1 = { 1, { 2, 3, {4, 5, 6} } };
S s2 = { 1, 2, 3, 4, 5, 6 }; // same, but with brace elision
S s3{ 1, {2, 3, {4, 5, 6} } }; // same, using direct-list-initialization syntax
S s4{ 1, 2, 3, 4, 5, 6 }; // error in C++11: brace-elision only allowed with equals sign
// okay in C++14

int ar[] = { 1,2,3 }; // ar is int[3]
//int ab[](1, 2, 3); // (C++20) ab is int[3]
//char cr[3] = {‘a’, ‘b’, ‘c’, ‘d’}; // too many initializer clauses
char cr[3] = { ‘a’ }; // array initialized as {‘a’, ‘’, ‘’}

int ar2d1[2][2] = { {1, 2}, {3, 4} }; // fully-braced 2D array: {1, 2}
//{3, 4}
int ar2d2[2][2] = { 1, 2, 3, 4 }; // brace elision: {1, 2}
//{3, 4}
int ar2d3[2][2] = { {1}, {2} }; // only first column: {1, 0}
//{2, 0}

std::array std_ar2{ {1,2,3} };// std::array is an aggregate
std::array std_ar1 = { 1, 2, 3 }; // brace-elision okay

int ai[] = { 1, 2.0 }; // narrowing conversion from double to int:
// error in C++11, okay in C++03

std::string ars[] = { std::string(“one”), // copy-initialization
“two”,// conversion, then copy-initialization
{‘t’, ‘h’, ‘r’, ‘e’, ‘e’} }; // list-initialization

U u1 = { 1 }; // OK, first member of the union
//U u2 = { 0, “asdf” }; // error: too many initializers for union
//U u3 = { “asdf” }; // error: invalid conversion to int

}

// aggregate
struct base1 { int b1, b2 = 42; };
// non-aggregate
struct base2 {
base2() : b3(42) {}
int b3;
int b4;
};
// aggregate only since C++17
struct derived : base1, base2 { int d; };
//derived d1{ {1, 2}, { }, 4 }; // d1.b1 = 1, d1.b2 = 2,d1.b3 = 42, d1.d = 4 // before C++17: not an aggregate, as it inherites from a non-aggregate
//derived d2{ {}, { }, 4 }; // d2.b1 = 0, d2.b2 = 42, d2.b3 = 42, d2.d = 4 // before C++17: not an aggregate, as it inherites from a non-aggregate
base1 b1 = {1,2}; // aggregate initialization
base2 b2 = {3,4}; // not an aggregate, aggregate initialization is not allowed

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[SOLVED] CS计算机代考程序代写 // from: https://en.cppreference.com/w/cpp/language/aggregate_initialization
30 $