[SOLVED] CS c++ cache computer architecture mips Pipelining 1

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Pipelining 1
CS 154: Computer Architecture Lecture #14
Winter 2020
Ziad Matni, Ph.D.
Dept. of Computer Science, UCSB

Administrative
Talk is on MONDAY, MARCH 9th in our usual class Will take attendance
We only have 3 more lecturesL please everybody control your emotions Pipelining and start w/ Memory Caching
Final Exam info:
Tuesday, March 17th at 12:00 (not 12:30!!!) in this classroom
Arrive 10 mins early randomized seating
Cumulative Exam
Will allow some notes exact details to follow
Study guide/example Qs will be issued by this weekend
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Lecture Outline
Data Hazards in Pipelining
Pipeline Designs and Operation
Examples with some Instructions
Diagramming Pipelined Instructions
Control Lines for Pipelines
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Comparison of Per-Instruction Time
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Hazards
Situations that prevent starting the next instruction in the next cycle
Structure hazards
A required resource is busy
Data hazard
Need to wait for previous instruction to complete its data read/write
Control hazard
Deciding on control action depends on previous instruction
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Structure Hazards
Conflict for use of a resource
In MIPS pipeline with a single memory
Load/store requires data access
Instruction fetch would have to stall for that cycle Would cause a pipeline bubble
Hence, pipelined datapaths require separate instruction/data memories
Or separate instruction/data caches
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Data Hazards
An instruction depends on completion of data access by a previous instruction
Example 1:
add $s0, $t0, $t1 sub $t2, $s0, $t3
Forwarding: possible if destination stage is later in time than source stage
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Forwarding: Use result
when it is computed
Dont wait for it to be stored
in a register
Requires extra connections
in the datapath

Data Hazards
Example 2:
lw $s0, 20($t1) sub $t2, $s0, $t3
Cannot forward back in time!!
Forwarding: not possible in this example, UNLESS
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Data Hazards
Example 2:
lw $s0, 20($t1) sub $t2, $s0, $t3
Forwarding: not possible in this example, UNLESS we put in a stalling instruction (aka pipeline stall or bubble) between them
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Code Scheduling to Avoid Stalls
Reorder code to avoid use of load result in the next instruction
Example: C++ code for Original
lw $tl, 0($t0)
lw $t2, 4($t0)
add $t3, $tl, $t2
sw $t3, 12($t0)
lw $t4, 8($t0)
add $t5, $tl, $t4
sw $t5, 16($t0)
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a = b + e; c = b + f;
Re-Ordered
lw $tl, 0($t0) lw $t2, 4($t0) lw $t4, 8($t0) add $t3, $tl, $t2 sw $t3, 12 ($t0) add $t5, $tl,$t4 sw $t5, 16 ($t0)
Matni, CS154, Wi20
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Move here and save 2 cycles

Control Hazard
Comes from need to make a decision based on the results of one instruction while others are executing
Think of the laundry example if we were worried that the soap amount was enough based on how clean the loads come out
Branch determines flow of control
Fetching next instruction depends on branch outcome
Pipeline cant always fetch correct instruction because it is still working on ID stage of branch
In MIPS pipeline
Need to compare registers and compute target early in the pipeline Needs added hardware to do it in ID stage
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Possible Solution: Stall on Branch
Wait until branch outcome is determined before fetching next instruction
Since the pipeline cannot possibly know what the next instruction should be, since it only just received the branch instruction from memory
This is the instruction after branching:
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Better Solution: Predict the Branch!
Predict outcome of branch
Only stalls if prediction is wrong
This option does not slow down the pipeline when its correct!
In MIPS pipeline,
it is simplest to predict if branches are not taken
When correct, the pipeline proceeds at full speed
When branches are taken, then the pipeline purposely stalls Fetch instruction after branch, with no delay
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MIPS with Predict Not Taken
Prediction Correct
that branch not needed
Prediction Incorrect
that branch not needed (simplified e.g.)
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MIPS with Predict Not Taken
Prediction Correct
that branch not needed
Prediction Incorrect
that branch not needed (simplified e.g.)
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More-Realistic Branch Predictions
Static branch prediction
Based on typical branch behavior
Example: loop and if-statement branches Predict backward branches taken
Predict forward branches not taken
Not the best, but better than always predicting no-branch Dynamic branch prediction
Hardware measures actual branch behavior e.g., it record recent history of each branch
Assume future behavior will continue the trend
When wrong, stall while re-fetching, and update history Tends to be accurate ~90% of the time
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Pipeline Summary
Pipelining improves performance by increasing instruction throughput
Executes multiple instructions in parallel Each instruction still has the same latency
Subject to hazards
Structure, data, control
Instruction set design affects complexity of pipeline implementation
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MIPS Pipelined Datapath: Requirements
Based on Single-Cycle Datapath Design
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Example
Instructions executed using the single-cycle datapath assuming pipelined execution.
In laundry analogy, we might have a basket between each pair of stages to hold the clothes for the next step
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MIPS Pipelined Datapath
Need registers between stages to hold information produced in previous cycle
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MIPS Pipelined Datapath for lw instruction: IF
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Highlight the right half of registers or memory when they are being read
Highlight the left half when they are being written

MIPS Pipelined Datapath for lw instruction: IF

Highlight the right half of registers or memory when they are being read
Highlight the left half when they are being written
Instruction is read from memory using the address in the PC
Placed in the IF/ID pipeline register.
PC address is incremented by 4 and then written back into the PC to be ready for the next clock cycle.
Incremented address is also saved in the IF/ID pipeline register
It could be needed later for an instruction, such as beq
(i.e. for prediction)
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MIPS Pipelined Datapath for lw instruction: ID
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MIPS Pipelined Datapath for lw instruction: ID
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Instruction portion of the IF/ID pipeline register supplies the:
16b immed. field (then sign extended)
2 register numbers to read
All three values are stored in the ID/EX pipeline reg. (along w/ PC address)
Transfer everything that might be needed by any instruction during a later clock cycle.

MIPS Pipelined Datapath for lw instruction: EX
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Instruction reads the contents of register 1 and the sign-extended immediate from the ID/EX pipeline register and adds them using the ALU.
Sum is placed in the EX/MEM pipeline register.
MIPS Pipelined Datapath for lw instruction: EX
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MIPS Pipelined Datapath for lw instruction: MEM
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MIPS Pipelined Datapath for lw instruction: MEM
Instruction reads the data memory using the address from the EX/MEM pipeline register
Loads the data into the MEM/WB pipeline register.
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MIPS Pipelined Datapath for lw instruction: WB
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MIPS Pipelined Datapath for lw instruction: WB
Instruction reads data from the MEM/WB pipeline register.
Writes it back into the register file.
What could be wrong here?
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The instruction in the IF/ID pipeline register supplies the write register number (rd), BUT the writing occurs at the end of the load instruction!
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We need to preserve the rd number in the load instruction

Corrected Pipelined Datapath
Otherwise load instruction wouldnt work properly
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Summary (so far)
To pass something from an early pipe stage to a later pipe stage, the information must be placed in a pipeline register
Otherwise, the information is lost when the next instruction enters that pipeline stage.
Each logical component of the datapath can be used only within a single pipeline stage.
We have seen 2 types of representations:
multiple-clock-cycle pipeline diagrams single-clock-cycle pipeline diagrams
Overview, fewer details Full details
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Multiple-Clock-Cycle Pipeline Diagrams of Five Instructions
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Single-Clock-Cylce Pipeline Diagram of Five Instructions Corresponding to Clock Cycle 5
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Simplified Pipeline Control Diagram (seems familiar?)
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Control Lines for the Last 3 Pipeline Stages
These are derived from the instruction
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Same control signals that we learned earlier, but this time they are ferried across the pipelines
See tables in Fig. 4.48, 4.49 in textbook

YOUR TO-DOs for the Week
Finish Lab 7 by Sunday
New Lab 8 (last one!) will be issued later on
this week
Due next week, which is last week of classesL
3/3/20
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[SOLVED] CS c++ cache computer architecture mips Pipelining 1
$25