[SOLVED] CS代考 CS 15-213, Fall 2008 Exam 1

Andrew login ID: Full Name:
Recitation Section:
CS 15-213, Fall 2008 Exam 1
Thurs. September 25, 2008

Copyright By PowCoder代写加微信 assignmentchef

Instructions:
• Make sure that your exam is not missing any sheets, then write your full name, Andrew login ID, and recitation section (A–H) on the front.
• Write your answers in the space provided for the problem. If you make a mess, clearly indicate your final answer.
• The exam has a maximum score of 72 points.
• The problems are of varying difficulty. The point value of each problem is indicated. Pile up the easy
points quickly and then come back to the harder problems.
• This exam is OPEN BOOK. You may use any books or notes you like. No calculators or other electronic devices are allowed.
• Good luck!
TOTAL (72):
Page 1 of 10

Problem 1. (8 points):
For this problem, assume the following:
• We are running code on an 8-bit machine using two’s complement arithmetic for signed integers. • short integers are encoded using 4 bits.
• Sign extension is performed whenever a short is cast to an int
The following definitions are used in the table below:
short sa = -6;
int b = 2*sa;
short sc = (short)b; int x = -64; unsigned ux = x;
Fill in the empty boxes in the table. If the expression is cast to or stored in a short, use a 4-bit binary representation. Otherwise assume an 8-bit binary representation. The first 2 lines are given to you as examples, and you need not fill in entries marked with “—”.
Expression
Decimal Representation
Binary Representation
T Max − T2 of 10

Problem 2. (10 points):
Assume we are using a machine where data type int uses a 32-bit, two’s complement representation, and right shifting is performed arithmetically. Data type float uses a 32-bit IEEE floating-point representation.
Consider the following definitions.
int i = hello();
float fi = i;
Answer the following questions. For each C-language expression in the first column, either
1. Mark that it is TRUE of all possible values returned by function hello(), and provide an explana-
tion of why it is true.
2. Mark that it is possibly FALSE, and provide a counter-example.
True/False
Explanation/Counter-example
(iˆ ∼(i>>31))<0-(i | (∼i + 1)) > 0
i>0 ⇒ i+(int)fi>0
fi>0 ⇒ fi+(float)i>0
i & 1 == ((int) fi) & 1
Page 3 of 10

Problem 3. (12 points):
Consider the following two 8-bit floating point representations based on the IEEE floating point format. Neither has a sign bit—they can only represent nonnegative numbers.
1. Format A
• There are k = 3 exponent bits. The exponent bias is 3.
• There are n = 5 fraction bits. 2. Format B
• There are k = 5 exponent bits. The exponent bias is 15. • There are n = 3 fraction bits.
Fill in the blanks in the table below by converting the given values in each format to the closest possible value in the other format. Express values as whole numbers (e.g., 17) or as fractions (e.g., 17/64). If necessary, you should apply the round-to-even rounding rule.
Page 4 of 10

Problem 4. (9 points):
Consider the following x86 64 assembly code:
# On entry: %rdi = M, %esi = n
# Note: nopl is simply a nop instruction for alignment purposes 0000000000400500 :
400500: 85 f6 400502: 7e 2a 400504: 31 c0 400506: 48 8b 0f 400509: 31 d2 40050b: 0f 1f 44 400510: 44 8b 01 400513: 45 85 c0 400516: 7f 18 400518: 83 c2 01 40051b: 48 83 c1 40051f: 39 c2 400521: 7e ed 400523: 83 c0 01 400526: 48 83 c7 40052a: 39 c6 40052c: 7f d8 40052e: 31 c0 400530: f3 c3
test %esi,%esi
jle 40052e xor %eax,%eax
mov (%rdi),%rcx
xor %edx,%edx
nopl 0x0(%rax,%rax,1) mov (%rcx),%r8d
test %r8d,%r8d
jg 400530 add $0x1,%edx
add $0x4,%rcx
cmp %eax,%edx
jle 400510 add $0x1,%eax
add $0x8,%rdi
cmp %eax,%esi
jg 400506 xor %eax,%eax
Fill in the blanks of the corresponding C function:
int func(______ M, int n) { int i, j;
for (i = 0; ______; i++) { for (j = 0; ______; j++) {
return ____;
if (________________)
return ____;
Page 5 of 10

Problem 5. (6 points):
Consider the C code below, where H and J are constants declared with #define. int array1[H][J];
int array2[J][H];
int copy_array(int x, int y) { array2[y][x] = array1[x][y];
return 1; }
Suppose the above C code generates the following x86-64 assembly code:
# On entry: # %edi=x # %esi=y # copy_array:
movslq %edi,%rdi
movslq %esi,%rsi
movq %rdi, %rax
leaq (%rsi,%rsi,2), %rdx salq $5, %rax
subq %rdi, %rax
leaq (%rdi,%rdx,2), %rdx addq %rsi, %rax
movl array1(,%rax,4), %eax movl %eax, array2(,%rdx,4) movl $1, %eax
What are the values of H and J? H=
Page 6 of 10

Problem 6. (8 points):
Consider the following data structure declarations:
struct node { struct entry e; struct node *next;
struct entry { char a;
long c[2]; }
Below are given four C functions and five x86-64 code blocks.
char *one(struct node *ptr){ return &(ptr->e.a)+1;
long two(struct node *ptr){
return ((ptr->e.c)[0] = ptr->next);
char *three(struct node *ptr){ return &(ptr->next->e.a);
char four(struct node *ptr){ return ptr->e.b;
In the following table, next to the name of each C function, write the name of the x86-64 block that imple- ments it.
mov 0x18(%rdi), %rax
lea 0x18(%rdi), %rax
lea 0x1(%rdi), %rax
mov 0x18(%rdi), %rax mov %rax, 0x8(%rdi)
movsbl 0x1(%rdi), %rax
Function Name
Code Block
Page 7 of 10

Problem 7. (11 points):
The next problem concerns code generated by GCC for a function involving a switch statement. The code uses a jump to index into the jump table:
400519: jmpq *0x400640(,%rdi,8)
Using GDB, we extract the 8-entry jump table as:
0x400640: 0x0000000000400530 0x400648: 0x0000000000400529 0x400650: 0x0000000000400520 0x400658: 0x0000000000400529 0x400660: 0x0000000000400535 0x400668: 0x000000000040052a 0x400670: 0x0000000000400529 0x400678: 0x0000000000400530
The following block of disassembled code implements the branches of the switch statement:
# on entry: %rdi
400510: mov
400513: cmp
400517: ja
400519: jmpq
400520: mov
400523: add
400526: salq
400529: retq
40052a: mov
40052d: xor
400530: lea
400534: retq
400535: mov
400538: retq
= a, %rsi = b, %rdx = c $0x5,%rax
400529 *0x400640(,%rdi,8) %rdx,%rax
0x70(%rdx),%rax
Page 8 of 10

Fill in the blank portions of C code below to reproduce the function corresponding to this object code. You can assume that the first entry in the jump table is for the case when a equals 0.
long test(long a, long b, long c) {
long answer = _____; switch(a)
c = _____;
/* Fall through */
answer = _____;
answer = _____;
answer = _____;
answer = _____;
return answer;
Page 9 of 10

Problem 8. (8 points):
A. Show how the struct above would appear on a 32-bit Windows machine (primitives of size k are k- byte aligned). Label the bytes that belong to the various fields with their names and clearly mark the end of the struct. Use hatch marks to indicate bytes that are allocated in the struct but are not used.
+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+ ||||||||||||||||| +–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+
+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+ ||||||||||||||||| +–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+
+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+ ||||||||||||||||| +–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+
B. Rearrange the above fields in foo to conserve the most space in the memory below. Label the bytes that belong to the various fields with their names and clearly mark the end of the struct. Use hatch marks to indicate bytes that are allocated in the struct but are not used.
+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+ ||||||||||||||||| +–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+
+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+ ||||||||||||||||| +–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+
+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+ ||||||||||||||||| +–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+–+
C. How many bytes of the struct are wasted in part A?
D. How many bytes of the struct are wasted in part B? Page 10 of 10

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