CHAPTER 2 Estimating Probabilities
Machine Learning
Copyright c 2017. Tom M. Mitchell. All rights reserved. *DRAFT OF January 26, 2018*
*PLEASE DO NOT DISTRIBUTE WITHOUT AUTHORS PERMISSION*
This is a rough draft chapter intended for inclusion in the upcoming second edition of the textbook Machine Learning, T.M. Mitchell, McGraw Hill. You are welcome to use this for educational purposes, but do not duplicate or repost it on the internet. For online copies of this and other materials related to this book, visit the web site www.cs.cmu.edu/tom/mlbook.html. Please send suggestions for improvements, or suggested exercises, to [email protected].
Many machine learning methods depend on probabilistic approaches. The reason is simple: when we are interested in learning some target function f : X Y , we can more generally learn the probabilistic function P(Y |X ). By using a probabilistic approach, we can design algorithms that learn func- tions with uncertain outcomes (e.g., predicting tomorrows stock price) and that incorporate prior knowledge to guide learning (e.g., a bias that tomor- rows stock price is likely to be similar to todays price). This chapter de- scribes joint probability distributions over many variables, and shows how they can be used to calculate a target P(Y|X). It also considers the problem of learning, or estimating, probability distributions from training data, pre- senting the two most common approaches: maximum likelihood estimation
and maximum a posteriori estimation.
1 Joint Probability Distributions
The key to building probabilistic models is to define a set of random variables, and to consider the joint probability distribution over them. For example, Table 1 defines a joint probability distribution over three random variables: a persons
1
Copyright c 2016, Tom M. Mitchell. 2
Gender HoursWorked Wealth
probability
female female female female
< 40.5 poor < 40.5 rich 40.5 poor 40.5 richmale < 40.5 poor male < 40.5 rich male 40.5 poor male 40.5 rich 0.2531 0.0246 0.0422 0.0116 0.3313 0.0972 0.1341 0.1059Table 1: A Joint Probability Distribution. This table defines a joint probability distri- bution over three random variables: Gender, HoursWorked, and Wealth.Gender, the number of HoursWorked each week, and their Wealth. In general, defining a joint probability distribution over a set of discrete-valued variables in- volves three simple steps:1. Define the random variables, and the set of values each variable can take on. For example, in Table 1 the variable Gender can take on the value male or female, the variable HoursWorked can take on the value < 40.5 or 40.5, and Wealth can take on values rich or poor.2. Create a table containing one row for each possible joint assignment of val- ues to the variables. For example, Table 1 has 8 rows, corresponding to the 8 possible ways of jointly assigning values to three boolean-valued variables. More generally, if we have n boolean valued variables, there will be 2n rows in the table.3. Define a probability for each possible joint assignment of values to the vari- ables. Because the rows cover every possible joint assignment of values, their probabilities must sum to 1.The joint probability distribution is central to probabilistic inference, because once we know the joint distribution we can answer every possible probabilistic question that can be asked about these variables. We can calculate conditional or joint probabilities over any subset of the variables, given their joint distribution. This is accomplished by operating on the probabilities for the relevant rows in the table. For example, we can calculate: The probability that any single variable will take on any specific value. For example, we can calculate that the probability P(Gender = male) = 0.6685 for the joint distribution in Table 1, by summing the four rows for which Gender = male. Similarly, we can calculate the probability P(Wealth = rich) = 0.2393 by adding together the probabilities for the four rows cover- ing the cases for which Wealth=rich. Copyright c 2016, Tom M. Mitchell. 3 Theprobabilitythatanysubsetofthevariableswilltakeonaparticularjoint assignment. For example, we can calculate that the probability P(Wealth=rich Gender=female) = 0.0362, by summing the two table rows that satisfy this joint assignment. Any conditional probability defined over subsets of the variables. Recall the definition of conditional probability P(Y |X ) = P(X Y )/P(X ). We can calculate both the numerator and denominator in this definition by sum- ming appropriate rows, to obtain the conditional probability. For example, according to Table 1, P(Wealth=rich|Gender=female) = 0.0362/0.3315 = 0.1092.To summarize, if we know the joint probability distribution over an arbi- trary set of random variables {X1…Xn}, then we can calculate the conditional and joint probability distributions for arbitrary subsets of these variables (e.g., P(Xn|X1…Xn1)). In theory, we can in this way solve any classification, re- gression, or other function approximation problem defined over these variables, and furthermore produce probabilistic rather than deterministic predictions for any given input to the target function.1 For example, if we wish to learn to predict which people are rich or poor based on their gender and hours worked, we can use the above approach to simply calculate the probability distribution P(Wealth | Gender, HoursWorked).1.1 Learning the Joint DistributionHow can we learn joint distributions from observed training data? In the example of Table 1 it will be easy if we begin with a large database containing, say, descrip- tions of a million people in terms of their values for our three variables. Given a large data set such as this, one can easily estimate a probability for each row in the table by calculating the fraction of database entries (people) that satisfy the joint assignment specified for that row. If thousands of database entries fall into each row, we will obtain highly reliable probability estimates using this strategy.In other cases, however, it can be difficult to learn the joint distribution due to the very large amount of training data required. To see the point, consider how our learning problem would change if we were to add additional variables to describe a total of 100 boolean features for each person in Table 1 (e.g., we could add do they have a college degree?, are they healthy?). Given 100 boolean features, the number of rows in the table would now expand to 2100, which is greater than 1030. Unfortunately, even if our database describes every single person on earth we would not have enough data to obtain reliable probability estimates for most rows. There are only approximately 1010 people on earth, which means that for most of the 1030 rows in our table, we would have zero training examples! This1Of course if our random variables have continuous values instead of discrete, we would need an infinitely large table. In such cases we represent the joint distribution by a function instead of a table, but the principles for using the joint distribution remain unchanged. Copyright c 2016, Tom M. Mitchell. 4is a significant problem given that real-world machine learning applications often use many more than 100 features to describe each example for example, many learning algorithms for text analysis use millions of features to describe text in a given document.To successfully address the issue of learning probabilities from available train- ing data, we must (1) be smart about how we estimate probability parameters from available data, and (2) be smart about how we represent joint probability distribu- tions.2 Estimating ProbabilitiesLet us begin our discussion of how to estimate probabilities with a simple exam- ple, and explore two intuitive algorithms. It will turn out that these two intuitive algorithms illustrate the two primary approaches used in nearly all probabilistic machine learning algorithms.In this simple example you have a coin, represented by the random variable X. If you flip this coin, it may turn up heads (indicated by X = 1) or tails (X = 0). The learning task is to estimate the probability that it will turn up heads; that is, to estimate P(X = 1). We will use to refer to the true (but unknown) probability of heads (e.g., P(X = 1) = ), and use to refer to our learned estimate of this true . You gather training data by flipping the coin n times, and observe that it turns up heads 1 times, and tails 0 times. Of course n = 1 + 0.What is the most intuitive approach to estimating = P(X = 1) from this train- ing data? Most people immediately answer that we should estimate the probability by the fraction of flips that result in heads:Probability estimation Algorithm 1 (maximum likelihood). Given observed training data producing 1 total heads, and 0 total tails, output the estimate= 1 1 + 0For example, if we flip the coin 50 times, observing 24 heads and 26 tails, then we will estimate the probability P(X = 1) to be = 0.48.This approach is quite reasonable, and very intuitive. It is a good approach when we have plenty of training data. However, notice that if the training data is very scarce it can produce unreliable estimates. For example, if we observe only 3 flips of the coin, we might observe 1 = 1 and 0 = 2, producing the estimate = 0.33. How would we respond to this? If we have prior knowledge about the coin for example, if we recognize it as a government minted coin which is likely to have close to 0.5 then we might respond by still believing the probability is closer to 0.5 than to the algorithm 1 estimate = 0.33. This leads to our second intuitive algorithm: an algorithm that enables us to incorporate prior assumptions along with observed training data to produce our final estimate. In particular, Algorithm 2 allows us to express our prior assumptions or knowledge about the Copyright c 2016, Tom M. Mitchell. 5coin by adding in any number of imaginary coin flips resulting in heads or tails. We can use this option of introducing 1 imaginary heads, and 0 imaginary tails, to express our prior assumptions:Probability estimation Algorithm 2. (maximum a posteriori prob- ability). Given observed training data producing 1 observed heads, and 0 observed tails, plus prior information expressed by introduc- ing 1 imaginary heads and 0 imaginary tails, output the estimate = ( 1 + 1 )(1 +1)+(0 +0)Note that Algorithm 2, like Algorithm 1, produces an estimate based on the proportion of coin flips that result in heads. The only difference is that Algo- rithm 2 allows including optional imaginary flips that represent our prior assump- tions about , in addition to actual observed data. Algorithm 2 has several attrac- tive properties: It is easy to incorporate our prior assumptions about the value of by ad- justing the ratio of 1 to 0. For example, if we have reason to assume that = 0.7 we can add in 1 = 7 imaginary flips with X = 1, and 0 = 3 imaginary flips with X = 0. It is easy to express our degree of certainty about our prior knowledge, by adjusting the total volume of imaginary coin flips. For example, if we are highly certain of our prior belief that = 0.7, then we might use priors of 1 =700 and 0 =300 instead of 1 =7 and 0 =3. By increasing the volume of imaginary examples, we effectively require a greater volume of contradictory observed data in order to produce a final estimate far from our prior assumed value. If we set 1 = 0 = 0, then Algorithm 2 produces exactly the same estimate as Algorithm 1. Algorithm 1 is just a special case of Algorithm 2. Asymptotically, as the volume of actual observed data grows toward infin- ity, the influence of our imaginary data goes to zero (the fixed number of imaginary coin flips becomes insignificant compared to a sufficiently large number of actual observations). In other words, Algorithm 2 behaves so that priors have the strongest influence when observations are scarce, and their influence gradually reduces as observations become more plentiful.Both Algorithm 1 and Algorithm 2 are intuitively quite compelling. In fact,these two algorithms exemplify the two most widely used approaches to machine learning of probabilistic models from training data. They can be shown to follow from two different underlying principles. Algorithm 1 follows a principle called Maximum Likelihood Estimation (MLE), in which we seek an estimate of that Copyright c 2016, Tom M. Mitchell. 6 Figure 1: MLE and MAP estimates of as the number of coin flips grows. Data was generated by a random number generator that output a value of 1 with probability = 0.3, and a value of 0 with probability of (1 ) = 0.7. Each plot shows the two estimates of as the number of observed coin flips grows. Plots on the left correspond to values of 1 and 0 that reflect the correct prior assumption about the value of , plots on the right reflect the incorrect prior assumption that is most probably 0.4. Plots in the top row reflect lower confidence in the prior assumption, by including only 60 = 1 + 0 imaginary data points, whereas bottom plots assume 120. Note as the size of the data grows, the MLE and MAP estimates converge toward each other, and toward the correct estimate for .maximizes the probability of the observed data. In fact we can prove (and will, below) that Algorithm 1 outputs an estimate of that makes the observed data at least as probable as any other possible estimate of . Algorithm 2 follows a dif- ferent principle called Maximum a Posteriori (MAP) estimation, in which we seek the estimate of that is itself most probable, given the observed data, plus back- ground assumptions about its value. Thus, the difference between these two prin- ciples is that Algorithm 2 assumes background knowledge is available, whereas Algorithm 1 does not. Both principles have been widely used to derive and to justify a vast range of machine learning algorithms, from Bayesian networks, to linear regression, to neural network learning. Our coin flip example represents just one of many such learning problems. The experimental behavior of these two algorithms is shown in Figure 1. HereCopyright c 2016, Tom M. Mitchell. 7the learning task is to estimate the unknown value of = P(X = 1) for a boolean- valued random variable X, based on a sample of n values of X drawn indepen- dently (e.g., n independent flips of a coin with probability of heads). In this figure, the true value of is 0.3, and the same sequence of training examples is used in each plot. Consider first the plot in the upper left. The blue line shows the estimates of produced by Algorithm 1 (MLE) as the number n of training examples grows. The red line shows the estimates produced by Algorithm 2, us- ing the same training examples and using priors 0 = 42 and 1 = 18. This prior assumption aligns with the correct value of (i.e., [1/(1 + 0)] = 0.3). Note that as the number of training example coin flips grows, both algorithms converge toward the correct estimate of , though Algorithm 2 provides much better esti- mates than Algorithm 1 when little data is available. The bottom left plot shows the estimates if Algorithm 2 uses even more confident priors, captured by twice as many imaginary examples (0 = 84 and 1 = 36). The two plots on the right side of the figure show the estimates produced when Algorithm 2 (MAP) uses incor- rect priors (where [1/(1 + 0)] = 0.4). The difference between the top right and bottom right plots is again only a difference in the number of imaginary examples, reflecting the difference in confidence that should be close to 0.4.2.1 Maximum Likelihood Estimation (MLE)Maximum Likelihood Estimation, often abbreviated MLE, estimates one or more probability parameters based on the principle that if we observe training data D, we should choose the value of that makes D most probable. When applied to the coin flipping problem discussed above, it yields Algorithm 1. The definition of the MLE in general isMLE = argmaxP(D|) (1) The intuition underlying this principle is simple: we are more likely to observe data D if we are in a world where the appearance of this data is highly probable. Therefore, we should estimate by assigning it whatever value maximizes the probability of having observed D.Beginning with this principle for choosing among possible estimates of , it is possible to mathematically derive a formula for the value of that provably maximizes P(D|). Many machine learning algorithms are defined so that they provably learn a collection of parameter values that follow this maximum likeli- hood principle. Below we derive Algorithm 1 for our above coin flip example, beginning with the maximum likelihood principle.To precisely define our coin flipping example, let X be a random variable which can take on either value 1 or 0, and let = P(X = 1) refer to the true, but possibly unknown, probability that a random draw of X will take on the value 1.2 Assume we flip the coin X a number of times to produce training data D, in which2A random variable defined in this way is called a Bernoulli random variable, and the proba- bility distribution it follows, defined by , is called a Bernoulli distribution. Copyright c 2016, Tom M. Mitchell. 8we observe X =1 a total of 1 times, and X =0 a total of 0 times. We further assume that the outcomes of the flips are independent (i.e., the result of one coin flip has no influence on other coin flips), and identically distributed (i.e., the same value of governs each coin flip). Taken together, these assumptions are that the coin flips are independent, identically distributed (which is often abbreviated to i.i.d.).The maximum likelihood principle involves choosing to maximize P(D|). Therefore, we must begin by writing an expression for P(D|), or equivalently P(1,0|) in terms of , then find an algorithm that chooses a value for that maximizes this quantity. To begin, note that if data D consists of just one coin flip, then P(D|) = if that one coin flip results in X = 1, and P(D|) = (1) if the result is instead X = 0. Furthermore, if we observe a set of i.i.d. coin flips such as D = {1, 1, 0, 1, 0}, then we can easily calculate P(D|) by multiplying together the probabilities of each individual coin flip:P(D = {1,1,0,1,0} | ) = (1)(1) = 3 (1)2In other words, if we summarize D by the total number of observed times 1 whenX =1 and the number of times 0 that X =0, we have in general P(D=1,0|)=1 (1)0 (2)The above expression gives us a formula for P(D = 1,0|). The quantity P(D|) is often called the data likelihood, or the data likelihood function because it expresses the probability of the observed data D as a function of . This likeli- hood function is often written L() = P(D|).Our final step in this derivation is to determine the value of that maximizes the data likelihood function P(D = 1,0|). Notice that maximizing P(D|) with respect to is equivalent to maximizing its logarithm, ln P(D|) with respect to , because ln(x) increases monotonically with x:argmaxP(D|) = argmaxlnP(D|) It often simplifies the mathematics to maximize lnP(D|) rather than P(D|), as is the case in our current example. In fact, this log likelihood is so common that it has its own notation, l() = ln P(D|).To find the value of that maximizes ln P(D|), and therefore also maximizes P(D|), we can calculate the derivative of lnP(D = 1,0|) with respect to , then solve for the value of that makes this derivative equal to zero. Because lnP(D|) is a concave function of , the value of where this derivative is zero will be the value that maximizes lnP(D|). First, we calculate the derivative of the log of the likelihood function of Eq. (2):l() = ln P(D|) ln[1(1)0] = Copyright c 2016, Tom M. Mitchell. 9 [1 ln + 0 ln(1)] == ln+ln(1) 10 = ln + ln(1) (1)1 0 (1) l()=1+ 1 (1) (3) where the last step follows from the equality ln x = 1 , and where the next to last 1 0(1)x x step follows from the chain rule f(x) = f(x) g(x). x g(x) xFinally, to calculate the value of that maximizes l(), we set the derivative in equation (3) to zero, and solve for .0=1 1 1 011=1 01 10 = 1(1 ) (1+0) = 1= 1 (4) 1 + 0Thus, we have derived in equation (4) the intuitive Algorithm 1 for estimating , starting from the principle that we want to choose the value of that maximizes P(D|).MLE = argmaxP(D|) = argmaxlnP(D|) = 1 (5) 1 + 0This same maximum likelihood principle is used as the basis for deriving many machine learning algorithms for more complex problems where the solution is not so intuitively obvious.2.2 Maximum a Posteriori Probability Estimation (MAP)Maximum a Posteriori Estimation, often abbreviated to MAP estimation, esti- mates one or more probability parameters based on the principle that we should choose the value of that is most probable, given the observed data D and our prior assumptions summarized by P().MAP = argmaxP(|D) When applied to the coin flipping problem discussed above, it yields Algorithm 2. Using Bayes rule, we can rewrite the MAP principle as:MAP = argmaxP(|D) = argmax P(D|)P() P(D)Copyright c 2016, Tom M. Mitchell. 10 and given that P(D) does not depend on , we can simplify this by ignoring thedenominator:MAP = argmaxP(|D) = argmaxP(D|)P() (6) Comparing this to the MLE principle described in equation (1), we see that whereas the MLE principle is to choose to maximize P(D|), the MAP principle instead maximizes P(D|)P(). The only difference is the extra P().To produce a MAP estimate for we must specify a prior distribution P() that summarizes our a priori assumptions about the value of . In the case where data is generated by multiple i.i.d. draws of a Bernoulli random variable, as in our coin flip example, the most common form of prior is a Beta distribution:11 (1)01P() = Beta(0,1) = B(0,1) (7)Here 0 and 1 are parameters whose values we must specify in advance to define a specific P(). As we shall see, choosing values for 0 and 1 corresponds to choosing the number of imaginary examples 0 and 1 in the above Algorithm 2. The denominator B(0,1) is a normalization term defined by the function B, which assures the probability integrates to one, but which is independent of .As defined in Eq. (6), the MAP estimate involves choosing the value of that maximizes P(D|)P(). Recall we already have an expression for P(D|) in Eq. (2). Combining this with the above expression for P() we have:MAP= arg max P(D|)P() 11 (1)01 B(0,1)= arg max 1 (1)0 1 +1 1 (1 )0 +0 1 B(0,1)= arg max= argmax 1+11 (1)0+01 (8) where the final line follows from the previous line because B(0,1) is indepen- dent of .How can we solve for the value of that maximizes the expression in Eq. (8)? Fortunately, we have already answered this question! Notice that the quantity we seek to maximize in Eq. (8) can be made identical to the likelihood function in Eq. (2) if we substitute (1 + 1 1) for 1 in Eq. (2), and substitute (0 + 0 1) for 0. We can therefore reuse the derivation of MLE beginning from Eq. (2) and ending with Eq. (4), simply by carrying through this substitution. Applying this same substitution to Eq. (4) implies the solution to Eq. (8) is thereforeMAP = argmaxP(D|)P() = (1 +1 1) (9) (1 +1 1)+(0 +0 1) Copyright c 2016, Tom M. Mitchell. 11Figure 2: Prior (left) and posterior (right) probability distributions on in a MAP estimate for . Consider estimating = P(X = 1) for a boolean valued (Bernoulli) random variable X. Suppose we set a prior P() defined by a Beta distribution with 0 = 3, 1 = 4, as shown on the left. Suppose further that we now observe data D con- sisting of 100 examples: 50 where we observe X = 1 and 50 where X = 0. Then the posterior probability P(|D) over given this observed data D, which is proportional to P(D|)P(), is another Beta distribution with 0 = 53,1 = 54, as shown on the right. Notice that both distributions assign non-zero probability to every possible value of between 0 and 1, though the posterior distribution has most of its probability mass near =0.5.Thus, we have derived in Eq. (9) the intuitive Algorithm 2 for estimating , starting from the principle that we want to choose the value of that maximizes P(|D). The number 1 of imaginary heads in Algorithm 2 is equal to 1 1, and the number 0 of imaginary tails is equal to 0 1. This same maximum a posteriori probability principle is used as the basis for deriving many machine learning algorithms for more complex problems where the solution is not so intu- itively obvious as it is in our coin flipping example.2.2.1 MAP Priors and PosteriorsWhy did we chose above to use the Beta(0,1) family of probability distributions to define our prior probability P() when calculating the MAP estimate MAP? We made this choice because the Beta distribution has a functional form that is the same as the data likelihood P(D|) in our problem, so that when we multiply these two forms together to get the quantity P(D|)P() , this product is easily expressed as yet another expression of this same functional form. Furthermore, in this product the 0 and 1 parameters that define our Beta distribution play exactly the same role as the observed data counts; that is, they capture the effect of the Beta prior P() in a form that is equivalent to specifying the number of imaginary examples used in our earlier Algorithm 23.Figure 2 shows an example of the prior P() and posterior P(|D) P(D|)P() distributions corresponding to a MAP estimate in our example.3More precisely, the number of imaginary examples i in Algorithm 2 is given by i 1.Copyright c 2016, Tom M. Mitchell. 12The Beta(0,1) distribution defined in Eq. (7) is called the conjugate prior for the binomial likelihood function 1 (1)0 , because the posterior distribu- tion P(D|)P() is also a Beta distribution. More generally, any P() is called the conjugate prior for a likelihood function L() = P(D|) if the posterior P(|D) is of the same form as P().3 Working with Other Probability DistributionsFormally, the probability distribution we considered above is called a Bernoulli distribution: it governs a random variable X which can take on two possible val- ues, 0 or 1, and this Bernoulli distribution is defined by the single parameter (i.e., P(X = 1) = , and P(X = 0) = (1). We will sometimes refer to a boolean-valued random variable which is governed by a Bernoulli distribution as a Bernoulli random variable. As noted above, the conjugate prior for estimating the parameter of a Bernoulli distribution is the Beta distribution.3.1 Discrete Valued Random Variables with Many ValuesIf we have a random variable that can take on more than two values then we need more than one parameter to describe the probability distribution for that variable. For example, consider a six-sided die which, when rolled, can come up with any of 6 possible results.A common approach to characterizing such n-valued random variables is touse a generalization of the Bernoulli distribution called a Categorical distribu-tion, where we assign a different probability to each possible value of the ran-dom variable. For example, we might model a six-sided die as a random vari-able X that can take on the values 1 through 6, and represent its probabilitydistribution by a vector of six different parameters = 1 …6, where theparameter i describes the probability that X will take on its ith value; that is,i = P(X = i). The likelihood function L() = P(D|) for estimating the vector of parameters from observed rolls of the die is a simple generalization of thelikelihood for estimating a Bernoulli distribution. It takes the form of a productL()=P(D|)=1 2…n,where indicatestheobservedcountoftimes 12niwhen the value X = i was observed in the data. Given a sample of data drawn from a particular Categorical distribution for a random variable that can take on n possible values, the maximum likelihood estimate for i is given byMLE = i (10) i 1 + . . . + nwhere j indicates the number of times the value X = j was observed in the data. Note that just like the case of a binary-valued random variable (see eq. 5), the MLE is simply the fraction of times the particular value was observed in the data.If we prefer a MAP estimate for an n-valued random variable governed by a Categorical distribution, we use the conjugate prior for the Categorical distribu- tion, which is called the Dirichlet distribution. Of course given that the Categorical Copyright c 2016, Tom M. Mitchell. 13distribution has n different i parameters, its prior will have to specify the proba- bility for each joint assignment of these n parameters. The Dirichlet distribution is a generalization of the Beta distribution, and has the form(11)(21) …(n1) P(1,…n)= 1 2 nwhere the denominator is again a normalizing function to assure that the total probability mass is 1, and where this normalizing function B(1,…,n) is inde- pendent of the vector of parameters = 1 …n and therefore can be ignored when deriving their MAP estimates.The MAP estimate for each i for a Categorial distribution is given byMAP = (i+i1) (11)i (1 +1 1)+…+(n +n 1)where j indicates the number of times the value X = j was observed in the data, and where the js are the parameters of the Dirichlet prior which reflects our prior knowledge or assumptions. Here again, we can view the MAP estimate as combining the observed data given by the j values with j 1 additional imaginary observations for X = j. Comparing this formula to the earlier formula giving the MAP estimate for a Bernoulli random variable (eq. 9), it is easy to see that this is a direct generalization of that simpler case, and that it again follows the intuition of our earlier Algorithm 2.4 What You Should KnowThe main points of this chapter include: Joint probability distributions lie at the core of probabilistic machine learn- ing approaches. Given the joint probability distribution P(X1 …Xn) over a set of random variables, it is possible in principle to compute any joint or conditional probability defined over any subset of these variables. Learning, or estimating, the joint probability distribution from training data can be easy if the data set is large compared to the number of distinct prob- ability terms we must estimate. But in many practical problems the data is more sparse, requiring methods that rely on prior knowledge or assump- tions, in addition to observed data. Maximumlikelihoodestimation(MLE)isoneoftwowidelyusedprinciples for estimating the parameters that define a probability distribution. This principle is to choose the set of parameter values MLE that makes the ob- served training data most probable (over all the possible choices of ):MLE = argmaxP(data|) B(1,…,n) Copyright c 2016, Tom M. Mitchell. 14In many cases, maximum likelihood estimates correspond to the intuitive notion that we should base probability estimates on observed ratios. For example, given the problem of estimating the probability that a coin will turn up heads, given 1 observed flips resulting in heads, and 0 observed flips resulting in tails, the maximum likelihood estimate corresponds exactly to taking the fraction of flips that turn up heads:1 1 + 0MLE = argmaxP(data|) = Maximiumaposterioriprobability(MAP)estimationistheotherofthetwo widely used principles. This principle is to choose the most probable value of , given the observed training data plus a prior probability distribution P() which captures prior knowledge or assumptions about the value of :MAP = argmaxP(|data) = argmaxP(data|)P() In many cases, MAP estimates correspond to the intuitive notion that we can represent prior assumptions by making up imaginary data which re- flects these assumptions. For example, the MAP estimate for the above coin flip example, assuming a prior P() = Bet a(0 + 1, 1 + 1), yields a MAP estimate which is equivalent to the MLE estimate if we simply add in an imaginary 1 heads and 0 tails to the actual observed 1 heads and 0 tails:MAP = argmaxP(data|)P() = EXERCISES(1 +1) (1 +1)+(0 +0) 1. In the MAP estimation of for our Bernoulli random variable X in this chapter, we used a Beta(0,1) prior probability distribution to capture our prior beliefs about the prior probability of different values of , before see- ing the observed data. Plot this prior probability distribution over , corresponding to the number of imaginary examples used in the top left plot of Figure 1 (i.e., 0 = 42,1 = 18). Specifically create a plot showing the prior probability (vertical axis) for each possible value of between 0 and 1 (horizontal axis), as represented by the prior distribution Beta(0,1). Recall the correspondence i = i + 1. Note you will want to write a simple computer program to create this plot. Above, you plotted the prior probability over possible values of . Now plot the posterior probability distribution over given that prior, plus observed data in which 6 heads (X = 1) were observed, along with 9 tails (X = 0).Copyright c 2016, Tom M. Mitchell. 15 Viewtheplotyoucreatedabovetovisuallydeterminetheapproximate Maximum a Posterior probability estimate MAP. What is it? What is the exact value of the MAP estimate? What is the exact value of the Maximum Likelihood Estimate MLE ? How do you think your plot of the posterior probability would change if you altered the Beta prior distribution to use 0 = 420,1 = 180? (hint: its ok to actually plot this). What if you changed the Beta prior to 0 = 32,1 = 28?5 AcknowledgementsI very much appreciate receiving helpful comments on earlier drafts of this chapter from Ondrej Filip, Ayush Garg, Akshay Mishra and Tao Chen. Andrew Moore provided the data summary shown in Table 1.REFERENCESMitchell, T (1997). Machine Learning, McGraw Hill. Wasserman, L. (2004). All of Statistics, Springer-Verlag.
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