[SOLVED] Cpsc 331 — assignment 2 2-3 trees

Suppose that E is an ordered type, that is, a nonempty set of values that have a total order. A
2-3-tree, for type E, is a finite rooted tree T (like a binary search tree or a red-black tree) that
satisfies the following 2-3 Tree Properties:(a) Every leaf in T stores an element of E. and the elements stored at the leaves of T are
distinct. Thus T represents a finite subset of E, namely, the set of values stored in the
leaves of T.(b) Every internal node of T has (exactly) either two or three children — which are each either
leaves or internal nodes of T.(c) If an internal node x has exactly two children — a first child, which is the root of a first
subtree of the subtree with root x, and a second child, which is the root of a second
subtree of the subtree with root x — then each of the values stored at the leaves of the
first subtree is less than each of the values stored at the leaves of the second subtree.(d) If an internal node x has exactly three children — a first child, second child and third
child, which are the roots of the first subtree, second subtree and third subtree of the
subtree with root x, respectively — then each of the values stored at the leaves of the first
subtree is less than each of the values stored at the leaves of the second subtree, and
1
(3, 9, 20)
1 3
(1, 3)
10 16 20
(5, 9) (10, 16, 20)
5 9Figure 1: A 2-3 Tree
each of the values stored at the leaves of the second subtree is less than each of the
values stores at the leaves of the third subtree.(e) If an internal node x of T has exactly two children then x stores a 2-tuple (m1, m2) —
where m1 is the largest value stored at any leaf of the first subtree, and m2 is the largest
value stored at any leaf of the second subtree of the subtree with root x.(f) If an internal node x of T has exactly three children then x stores a 3-tuple (m1, m2, m3)
— where m1 is the largest value stored at any leaf of the first subtree, m2 is the largest
value stored at any leaf of the second subtree, and m3 is the largest value stored at any
leaf of the third subtree of the subtree with root x.(g) Every leaf of T is at the same level of the tree — that is, the number of edges from the root
down to each leaf is the same.(h) Each node x of T is the root of a 2-3 tree as well. That is, the subtree with root x also
satisfies properties (a)–(g), for every node x in T.For example, the tree shown in Figure 1 is a 2-3 tree representing the set of integers
{1, 3, 5, 9, 10, 16, 20}.
Exercise: Confirm that this tree satisfies the “2-3 Tree Properties” that have now been given.Note: While a variety of references (that are available online) describe “2-3 Trees”, they do not
all describe the same kind of tree and, in particular, they do not necessarily describe the kind
of tree that is to be considered in this assignment!It will be useful to measure costs of operations on 2-3 trees in terms of the sizes of the sets
of elements of E that they represent, so that it will be helpful to bound the number of internal
nodes in this way too.
21. Let T be a nonempty 2-3 tree, so that it includes at least one node. Prove that if T
represents a subset S ⊆ E such that |S| = n ∈ N, then T has at most n − 1 internal
nodes.It follows that (if the uniform cost criterion is used to define this) the amount of storage space
needed to represent a non-empty 2-3 tree is at most linear in the size of the subset of E that it
represents.The depth of an empty 2-3 tree will be defined to be −1, just like the depth of an empty binary
search tree. Otherwise it is defined to be the number of edges in a longest path from the root
to a leaf in T — which is the number of edges in any path from the root down to any leaf in T,
by 2-3 Tree Property (g). Useful relationships between the depth of a 2-3 tree and the size of
the subset of E it represents can now be established.2. Let T be a non-empty 2-3 tree with depth d ∈ N and let n be the size of the subset of E
represented by T. Prove that 2
d ≤ n ≤ 3
d
.
3. Let d ∈ N and suppose that |E| ≥ 2
d
. Prove that there exists a non-empty 2-3 tree with
depth d, representing a subset of E with size exactly 2
d
.The proof used to complete Problem #3 can be modified to prove that if d ∈ N and |E| ≥ 3
d
then
there exists a non-empty 2-3 tree with depth d, representing a subset of E with size exactly 3
d
,
as well. Thus the bounds on sizes of a 2-3 tree, given in Problem #1, are tight. That is, they
cannot be improved.If a search algorithm is to be implemented as a method, provided by some 2-3 tree T, then it
can be considered as an algorithm that solves the following problem1
.Searching in This 2-3 TreePrecondition:
(a) This 2-3 tree, T, satisfies the 2-3 Tree Properties given above.
(b) A non-null key, of type E, is given as input.
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It is assumed here, and in the rest of the assignment, that null elements of E are never stored in a 2-3 tree —
and that no attempts to search for, insert or delete null elements are ever made.
3Postcondition:
(a) If the key is stored at a leaf in T then the leaf storing this key is returned as
output. A NoSuchElementException is thrown, otherwise.
(b) This 2-3 tree has not been changed, so it still satisfies the 2-3 Tree Properties.
Consider the following problem (which might also be solved using a method provided by this
2-3 tree) as well.Searching in a Subtree of This 2-3 Tree
Precondition:
(a) This 2-3 tree, T, satisfies the 2-3 Tree Properties given above.
(b) key is a non-null input of type E.
(c) x is a non-null in T that is also given as input.Postcondition:
(a) If the key is stored in the subtree of T with root x, then the leaf (in this subtree) storing x is returned as output. A NoSuchElementException is thrown
otherwise.(b) This 2-3 tree has not changed, so it still satisfies the 2-3 Tree Properties.
Suppose that get is an algorithm that correctly solves the second of these problems. Then the
algorithm shown in Figure 2 correctly solves the first of these problems, assuming that T.root
is a reference to the root of this 2-3 tree (so that T.root is null if and only if this is an empty
tree).It is possible to modify a corresponding algorithm, for searching in a subtree of a binary tree,
to obtain a simple recursive algorithm that solves the second problem. Since this is a 2-3 tree
and the input code x is not null, such an algorithm is as shown in Figure 3. It is assumed
here that if x is not a leaf then x.firstChild is its first child and x.firstMax is the largest
element stored in the first subtree.Similarly, if x is not a leaf then x.secondChild is its
second child and x.secondMax is the largest element stored in its second subtree — and
if x has three children then x.thirdChild is its third child and x.thirdMax is the largest
element stored in its third subtree.4. Prove that the depth of the subtree with root x is a bound function for the recursive
algorithm in Figure 3.
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node search(E key) {
1. if (T.root == null) {
2. Throw a NoSuchElementException
} else {
3. return get(key, root)
}
}
Figure 2: An algorithm to Search in this 2-3 Tree5. Prove that this algorithm correctly solves the “Searching in a Subtree of This 2-3 Tree”
problem that is given above.
6. Now let Tget(k) be an upper bound for the number of steps used by the algorithm when
the depth of the subtree with the input node x as root is k, for k ∈ N. Use the uniform
cost criterion to define this.Write a recurrence for Tget(k) as a function of k. Explain why your answer (which you
should make as precise as possible) is correct.
Note: You should be able to use your recurrence to show that Tget(0) ≤ 2, Tget(1) ≤ 7,
and Tget(2) ≤ 12.7. Use your recurrence to give an upper bound in closed form (that is, not involving a
summation or recurrence) for Tget(k) and prove that your bound is correct. Once again,
this should be a function of k and you should try to make it as precise as possible.Consider, now, the problem of inserting an element into the set stored by a 2-3 tree. If this
is to be implemented as a method supplied by this tree then it can be considered to solve the
following computational problem.Insertion into This 2-3 Tree
Precondition:
(a) This 2-3 tree, T, satisfies the 2-3 Tree properties given above.
(b) key is a non-null input of type E.
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node get(E key, node x) {
1. if (x is a leaf) {
2. if (key is equal to the element stored at x) {
3. return x
} else {
4. Throw a NoSuchElementException
}
5. } else if (x has two children) {
6. if (key ≤ x.firstMax) {
7. return get(key, x.firstChild)
} else {
8. return get(key, x.secondChild)
}
} else {
9. if (key ≤ x.firstMax) {
10. return get(key, x.firstChild)
11. else if (key ≤ x.secondMax) }
12. return get(key, x.secondChild)
} else {
13. return get(key, x.thirdChild)
}
}
}
Figure 3: An Incomplete Algorithm to Search in a Subtree of this 2-3 TreePostcondition:
(a) If the input key is not already in the subset of E represented by T then
it is added to this set (with this set being otherwise unchanged). An
ElementFoundException is thrown and the set is not changed, if the key
already belongs to this subset.(b) T satisfies the 2-3 Tree properties given above.
There are a few cases where this problem is easy, even though a node has to be added:
68. Briefly describe how to solve the above problem in the following cases.
(a) T is an empty tree, so that its root is a null node.
(b) T is not empty, but the set it represents has size one (so that its root is a leaf),Suppose, for the rest of this assignment, that addFirstElement is a simple algorithm (based
on your answer for part (a)) that takes an input key and can be used to complete the insertion
operation when T is empty, and that addSecondElement is another algorithm (based on your
answer for part (b)) that also takes an input key and can be used to complete the insertion
operation when the root of T is a leaf.A problem that arises, in other cases when 2-3 trees are modified, is that internal nodes temporarily have illegal numbers of children.
With that noted, consider the following Modified Tree Properties, which might be satisfied by
a rooted tree T when an operation is in progress.2(a) T satisfies 2-3 Tree Properties (a), (c), (d), (e), (f), and (g) — but not, necessarily, 2-3 Tree
Properties (b) or (h).
(b) Every internal node of T has (exactly) either one, two, three or four children — which are
each either leaves or internal nodes of T. There is at most one internal node of T that
has either (exactly) one or four children — all other internal nodes of T have either exactly
two children or exactly three children.(c) If an internal node x of T has exactly one child, then this is called a first child, which is
the root of a first subtree of the subtree with root x. In this case, x stores a 1-tuple (m1)
— where m1 is the largest value stored at any leaf of the first subtree of the subtree with
root x.(d) If an internal node x of T has exactly four children — a first child, second child, third
child and fourth child, which are the roots of the first subtree, second subtree, third
subtree and fourth subtree of the subtree with root x, respectively — then each of the
values stored at the leaves of the first subtree is less than each of the values stored at the
leaves of the second subtree, each of the values stored at the leaves of the second subtree
is less than each of the values stored at the leaves of the third subtree, and each of the
values stored at the leaves of the third subtree is less than each of the values stored at
the leaves of the fourth subtree.(e) If an internal node x of T has exactly four children then x stores a 4-tuple (m1, m2, m3, m4)
— where m1 is the largest value stored at any leaf of the first subtree, m2 is the largest
2As for the “2-3 Tree Properties”, some of these introduce terminology that will be used in the rest of the
assignment.7
value stored at any leaf of the second subtree, m3 is the largest value stored at any leaf of
the third subtree, and m4 is the largest value stored at any leaf of the fourth subtree of the
subtree with root x.(f) Each node x of T is the root of a rooted tree satisfying these properties as well. That is,
the subtree with root x also satisfies the above properties (a)–(e), for every node x in T.
Consider the following computational problem. It might not be clear why this is useful as
described here (but it will be).Precondition:
(a) This 2-3 tree, T, satisfies the 2-3 Tree properties given above.
(b) key is a non-null input of type E.
(c) x is a non-null node in T.(d) Either key is not stored in any leaf of T at all, or it is stored in a leaf of the subtree
of T with root x. If it is not stored at any of these leaves then it is possible to add
a new leaf storing this key, as a new child of one of the internal nodes in the
subtree with root x (without making other changes) in such a way that T satisfies
the “Modified Tree” properties.Postcondition:
(a) If the input key already belongs to the subset of E stored at the leaves in the
subtree of T with root x, then an ElementFoundException is thrown and T is
not changed.(b) If x is a leaf that stores an element of E that is not equal to the input key then a
NoSuchElementException is thrown and T is not changed.(c) If x is an internal node and the input key does not (initially) belong to the subset
of E stored at the leaves of the subtree of T with root x, then
• the input key is added to the subset of E stored at the leaves of T — which
is otherwise unchanged;
• either T satisfies the 2-3 Tree properties, given above, or T satisfies the
“Modified Tree” properties, given above, and x is now an internal node with
four children.Suppose, now, that insertIntoSubtree is a method that solves this computational problem.
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void insert(E key) {
1. if (T.root == null) {
2. addFirstElement(key)
3. } else if (T.root is a leaf) {
4. addSecondElement(key)
} else {
5. insertIntoSubtree(key, T.root)
6. if (T.root has four children) {
7. fixRoot()
}
}
}
Figure 4: An Algorithm for the “Insertion into This 2-3 Tree” Problem9. Suppose that the root of T is an internal node and the insertIntoSubtree method
is called with an input key ∈ E and with the root of T as input. Suppose, as well, that
the input key was not initially stored at any leaf of T — and that the root of T has four
children when the execution of this method ends.Briefly describe how to modify T so that the 2-3 Tree properties are restored (that is,
T is a 2-3 tree, once again) — without changing the subset of E represented by T, and
using only a constant number of steps.Suppose, now, that fixRoot is a method (with no inputs) that can be used to carry out the
computation described in the above question — and that this method is only applied when T
satisfies the above “Modified Tree” properties and its root is an internal node with four children.If the addFirstElement, addSecondElement, insertIntoSubtree and fixRoot methods are as described above, then an insert method that solves the “Insertion into This 2-3
Tree” problem is as shown in Figure 4 — where “ T.root” is a reference to the root of T.The only method that has not been described is the insertIntoSubtree method that solves
the above “Insertion into Subtree of This 2-3 Tree” problem, and which is used at line 5. It will
be useful to describe another pair of methods that will be used by this one.• Suppose that T satisfies the above “Modified Tree” properties and x is an internal node
of T, whose children are also internal nodes, such that either
– one of the children of x has four children, or
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– there is no internal node of T with either one or four children at all, so that T is a
2-3 tree.Suppose, as well, that if it called with input x, then the raiseSurplus method modifies T, without changing the subset of E represented by T or changing the position of x
in T (that is, without changing the distance or path from x to the root), so that T still
satisfies the above “Modified Tree” properties and either
– x has four children, or
– there is no internal node of T with either one or four children, so that T is a 2-3 tree.One way to perform this computation is to create an ArrayList of nodes, and another
ArrayList of the largest elements of E stored at the subtrees with these nodes as
roots. If none of the children of x has four children then the first ArrayList will simply
store these children.On the other hand, if some child of x has four children then this
should be replaced by two internal nodes, that each have two children, namely, two of
the four children of this child. In effect this child of x should be split into a pair of internal
nodes, increasing the number of children of x by one.With a bit of work, it can be confirmed that the number of steps needed for an execution
of this method is bounded by a constant.• Suppose, instead, that T is a 2-3 tree, x is an internal node of T whose children are
leaves, key is a non-null element of E that is not stored in any of the leaves of T, and
the the “Modified Tree” properties would still be satisfied if x was given another child,
namely, a new leaf storing the key.Suppose that, if called with the above key and internal node x as inputs, the method
addLeaf adds another leaf, storing the input key, as another child of x — so that T still
satisfies the “Modified Tree” properties, the subset of E represented has been changed
by including key (and making no other changes), and either x has four children or T is
a 2-3 tree.Once again, an ArrayList — of elements of E, to be stored at the children of x —
can be useful as part of an implementation this method, and this method can also be
implemented so that the number of steps used by an execution of the method is at most
a constant.Suppose, now, that the insertIntoSubtree method is as shown in Figure 5 on page 11. It
is assumed that x.firstChild, x.secondChild and x.thirdChild are the first, second
and third children of x, respectively, and that x.firstMax, x.secondMax and x.thirdMax
are the largest elements of E stored that the leaves of the subtrees of T with these children
of x as roots (when these children exist).10
void insertIntoSubtree(E key, node x) {
1. if (x is a leaf) {
2. Set e to the be the element of E stored at x
3. if (e is equal to the input key) {
4. Throw an ElementFoundException
} else {
5. Throw a NoSuchElementException
}
6, } else {
7. try {
8. if (x has two children) {
9. if (key ≤ x.firstMax) {
10. insertIntoSubtree(key, x.firstChild)
} else {
11. insertIntoSubtree(key, x.secondChild)
}
} else {
12. if (key ≤ x.firstMax) }
13. insertIntoSubtree(key, x.firstChild)
14. } else if (key ≤ x.secondMax) {
15. insertIntoSubtree(key, x.secondChild)
} else {
16. insertIntoSubtree(key, x.thirdChild)
}
};
17. raiseSurplus(x);
18. } catch (NoSuchElementException ex) {
19. addLeaf(key, x)
}
}
}
Figure 5: The insertIntoSubtree Method10. Suppose that the precondition for the “Insertion into Subtree of This 2-3 Tree” problem
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is satisfied and the insertIntoSubtree method is executed with the input key and a
node x that is a leaf in T. Tracing through the execution of the pseudocode shown in
Figure 5, as needed, explain why this method would terminate with the postcondition for
the “Insertion into Subtree of This 2-3 Tree” problem satisfied.11. Suppose, again, that the precondition for the “Insertion into Subtree of This 2-3 Tree”
problem is satisfied and the insertIntoSubtree method is executed with the key
and with an internal node x whose children are leaves, as inputs. Tracing through the
execution of the pseudocode shown in Figure 5, as needed, explain why this method
would terminate with the postcondition for the “Insertion into Subtree of This 2-3 Tree”
problem satisfied.Note: It might be helpful to compare the algorithms shown in Figures 3 and 5, and make
use of similarities in their structure and analysis.12. Describe how it can be proved that the insertIntoSubtree algorithm correctly solves
the “Insertion into Subtree of This 2-3 Tree” problem. Your answer does not need to be a
complete proof.However, you should identify the proof technique that is used, describe
what you are inducting on and give both an “Inductive Hypothesis” and “Inductive Claim”
whenever induction is to be used, and briefly describe any cases that must be handled
(including, but not limited to, situations considered when solving the above problems).13. Briefly describe how to prove that the number of steps executed by this method (when
it starts with its problem’s precondition satisfied) is in O(depth(x)) where x is the node
given as input — and where the Uniform Cost criterion is used to define this number of
steps.It is not necessary to give a complete proof. However, a bound function for this method
should be identified. and you should explain how the upper bound for the number of
steps, given above, is established.Once again, an examination of the insert method shown in Figure 4 should confirm that this
correctly solves the “Insertion into This 2-3 Tree” problem. Furthermore, the number of steps
used by an execution of this method is at most linear in the depth of this tree T.2-3 Trees: Deletions
Now consider the problem of deleting a value from the subset of E represented by a 2-3 tree.
This problem can be defined as follows.
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Deletion from This 2-3 TreePrecondition:
(a) This 2-3 tree, T, satisfies the 2-3 Tree properties given above.
(b) key is a non-null input of type E.Postcondition:
(a) If the input key belongs to the subset of E represented by T then
the key is removed from this set, which is otherwise unchanged. A
NoSuchElementException is thrown and T is not changed if the key does
not belong to this subset of E.(b) T satisfies the 2-3 Tree properties given above.
14. Describe related problems to be solved, algorithms that solve these problems, and
sketches of proofs of correctness, as needed to describe a solution for this computational problem too.
It will probably be helpful to consider the development of the solution for the “Insertion
into This 2-3 Tree” problem — that you have completed if you have solved the problems
before this — and describe significant differences between these two problems and their
solutions.• In both case some sort of “problem node” has probably been identified and then
moved from the area near a leaf up to the root of the tree. Say what kind of “problem
node” is involved for the “Deletion” problem instead of the “Insertion” one.• You may find that lots of the related problems are similar to the ones needed for
“Insertion” problem. Make sure that you clearly identify which problems are similar, as you go, and describe the differences in enough detail so that a reader can
understand this.One difference might be that grandchildren of a node should be considered, at a
place where the children a node got considered by the corresponding part of the
“Insertion” algorithm.Please allow lots of time to answer this question! It will probably required more
work (and a different kind of activity) than the questions before it.
1315. An incomplete Java program, TwoThreeTree.java, is now available. Details of the
implementation of a node for a 2-3 tree are consistent with the pseudocode given in this
assignment.Please complete this, by supplying code for the methods whose content currently consists of the phrase
// FOR YOU TO COMPLETE
(or something very similar, if there are typographical errors causing similar comments to
be used too).Do not change the code that has already been supplied: This may cause tests used
to evaluate your submission to fail. A complete solution has been prepared and tested,
so it has already been confirmed that no such changes are needed: If you feel that a
change is needed then this is probably evidence that you do not understand the problem
to be solved, or that you need to change the code you are including.However, you will need to introduce additional methods. It might be helpful to add one or
two more methods to reduce repetitiveness in the code that you would otherwise need to
provide to complete an implementation of an insert algorithm.You should also include
methods solving the additional computational problems you discussed when answering
the previous question, in order to complete the implementation of a delete algorithm.Additional code for testing — with information about how to use it — will be made available online very soon (and, in plenty of time for you to use it).
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