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[SOLVED] Cpsc 213 – assignment 8 dynamic control flow

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Goal
This week you continue from where you left off last week with poly.c to look at the use of
function pointers as parameters to the Dr. Racketish list primitives and as a way to implement
switch statements.
First you will create a small portion of Dr. Racket in C. You will start with a provided
implementation of a dynamically expandable list that knows its length. It’s like a list in Dr.
Racket (or Java), and unlike arrays in C that are fixed size and do not know how big they are
intrinsically. You will implement several functions that operate on lists using abstractionfunctions (i.e., C function pointers). You will test your program using a provided test file.
Finally, you will implement your own program that uses this list code.
Then you will move to switch statements. First you will examine the snippet we looked at in
class that gives you an example of a switch statement that is implemented by a jump table. Next,
you will examine a mystery assembly program to determine what it does.
Finally you will convert a C program that contains switch statements into one that uses only
goto’s and a jump table, instead of switch statements. Funny enough, this program is a C
version of the Java Simple Machine simulator that you used in Assignments 1-7, perhaps a fitting
way to bid a fond adieu to assembly language (for now).
Question 1: Using Function Pointers on Lists [45%]
In www.ugrad.cs.ubc.ca/~cs213/cur/assignments/a8/code.zip in the q1 subdirectory you will
find the following files: list.[ch], test.c, and Makefile.
Part 1: Implement the List Iterator Functions
The file list.c contain the skeleton implementation of several list operators adapted from Dr.
Racket: map1, map2, foldl, filter, and foreach. The two map functions are variations
on Dr. Racket’s map: map1 operates on one list and map2 on two.
Here’s a brief summary of what these functions do (google Dr. Racket for more):
• map takes a function and a set of lists (in our case one or two lists) and generates a new list
by applying the function to each element of the list;
(map + ‘(1,2,3) ‘(1 1 1)) => ‘(2 3 4)
• foldl takes a function, an initial value, and a set of lists (in our case just one list) and
generates the value that results from iterating over the list, calling the function on an
accumulated value, which starts at the specified initial value, and each element of the list in
turn, updating the accumulated value as it goes;
(fold + 0 ‘(1,2,3) => 6
• filter takes a function and a set of lists (in our case just one) and generates a new list that
contains the elements of the original list for which the function returns true;
(filter positive? ‘(-2,3,-8,5)) => (3,5)
• foreach takes a function and a list of lists (in out case just one) and calls the function for
each item in the list. It produces no value. (Note that the actual name of this function in Dr.
Racket is for-each, but we are going to call it foreach since you can’t have dashing is C
names.
(foreach print ‘(1 2 3)) => # printing the values 1, 2 and 3
Implement the TODO portions of list.c and use test.c, which uses these functions, to test
your code. Note that if you did Part 1 you already have two of these completed.
Your code must pass valgrind with no memory leaks. Be sure to run it with a variety of
inputs, include one with a long list of strings and integers (i.e., longer than 10 each).
Part 2: Implement a Program that Uses the List Iterator Functions
Finally, implement a program with no loops of any kind, other than an initial loop to read the
values of argv in Step 1 below, that uses list.[ch] to do the following, placing the
implementation in the file trunc.c.
The input to this program is a list of numbers and strings presented on the command line; e.g.,:
./trunc 4 apple 3 peach 5 banana 2 3 grape plum
The program uses the numbers to truncate the strings and prints the resulting strings, one per line
and, then the string concatenated (and separated by spaces), and finally the maximum string
length. So in this case the output would be.
appl
pea
banan
gr
plu
appl pea banan gr plu
5
Notice that the numbers are pared with strings based on their order in the string not their
proximity to each other and so the following would produce the same output.
./trunc 4 3 5 2 3 apple peach banana grape plum
Here is an outline of the program. You need to follow the steps listed. Take each step one at a
time. Implement a step and then test it by using list_foreach to print the list you create (be
sure to remove these extra prints, however, before you handin your solution; the only prints
allowed in the final version are those specified in Steps 7 and 8).
1. Read a list of strings from the command line and add them to a list. Note that argv
is an array of the command line arguments and argc is the length of that array.
Ignore argv[0] since that is the path to the program itself.
2. Iterate over the list to produce a new list of numbers (the list must actually be a list of
pointers to integers) that processes each string to determine if it is a number. If it is,
the corresponding value in this new list should be that number, otherwise it should be
a -1. Use the standard-C library procedure strtol to convert strings to numbers.
See its man page for details.
3. Iterate over the new list of numbers and the original list of strings together to produce
a new list of strings with a NULL value for every string that is a number (i.e., where
the number list is not -1).
4. Filter the number list to produce a new list with all negative values removed. The list
may thus be shorter than the original list.
5. Filter the string list to produce a new list with all NULLs removed.
6. Produce yet another list of strings that uses these two new lists of numbers and strings
to truncate strings, on a pairwise basis, taking the values in the number list to be the
maximum length of the entry in the string list. Recall that strings end with a null
(i.e., 0) character. For example if you had these two lists
l0 = [4,3,5,2,3]
l1 = [“apple”, “peach”, “banana”, “grape”, “plum”]
The new list of strings would be
l3 = [“appl”, “pea”, “banan”, “gr”, “plu”]
7. Print this revised list of strings, one string per line. Print nothing else on each line.
8. Then join this list into a single array, separated by spaces and print it on the next
line. If there are no input strings (or if all of the lengths are zero) then print the
empty string (i.e., a blank line).
s = “appl pea banan gr plu”;
9. Compute the maximum value in the numbers list and print it. Again; just print this
number.
10. Now rid your program of memory leaks by ensuring that everything that was
malloced in previous steps is freed. You must perform this step using one of the
second-class list functions in list.h.
Ensure that you program prints nothing other than what is specified in Steps 7-9.
Question 2: Switch Statements in Assembly [10%]
Examine the code for SB-switch, which you will find in the q2 subdirectory of
www.ugrad.cs.ubc.ca/~cs213/cur/assignments/a8/code.zip. Carefully read the three different
implementations in the C file. Run the assembly version in the simulator and observe what
happens. This part is not for marks, but it will help you with the next step.
The file q2.s contains uncommented assembly code that corresponds to a single C procedure
starting at address 0x300 and another procedure that sets up the stack and calls the first
procedure. Read this code and run it in the simulator. If you see a jump table, you might want to
add labels for the addresses it stores to make the code easier to read. Comment every line and
write an equivalent C program that is a likely candidate for the program the compiler used to
generate this assembly file (with the exception of the stack-setup code, which is only for the .s
file). Call this program q2.c.
For your solution to pass the handin tests it must declare a procedure named q2 that encapsulates
the code starting at address 0x300, that has the appropriate number of arguments (in the correct
order), and that returns the appropriate value. To test your code, you can include a main
procedure and any other procedures you like.
Question 3: Jump Tables in C [45%]
The file sm.c, found in the q3 subdirectory of www.ugrad.cs.ubc.ca/~cs213/cur/assignments/
a8/code.zip, is a C implementation of CPU.java; i.e., it is a sm213 virtual machine. It executes
sm213 machine code, but it doesn’t include an assembler and it doesn’t have a gui. As a result,
its a small C program that you should be able to read and understand.
Since the C version doesn’t contain an assembler, we’ll need to use the Java version to convert
assembly into machine code. To do this, run the simulator from the command line using the “-
d” option. For example, to convert foo.s into machine code type the following at the UNIX
command line.
java -jar SimpleMachine213.jar -d foo.s
The simulator places the resulting machine code in the file foo.m.
The provided code.zip file contains the following programs that have already been converted
to machine code; i.e., you have “.s” and “.m” versions of each of these programs.
When you run the C simulator you specify which file to execute and provide zero or more of the
following command line options.
For example, to run foo.m and print out the registers and memory locations 0x2000-0x2007,
type the following at the command line.
./sm -r -m 2000:2 foo.m
Lets start by reading sm.c, seeing how cool this is, and then making a small change.
simple-test A very simple test that includes only two instructions.
test A test that uses every instruction (except the double-indirect jumps).
a2-test The test.s file from Assignment 2 that tests ALU and memory instructions.
max Compute maximum value of a list of integers.
a6-q3 The Assignment 6 solution that finds the student with the median grade.
-p a Set the starting pc to address a (assumed to be in hex); default is first instruction.
-r Print the ending values of the register file.
-m a:c Print the ending value of memory at address a, continuing for c lines (4 bytes per
line). This option can be repeated to print multiple non-contiguous memory regions.
Read, Understand and Modify the C Simulator [10%]
Examine the fetch() and exec() procedures in sm.c. These are equivalent to the two
functions in CPU.java. They execute in sequence each clock tick to fetch an instruction from
memory and execute it. Read exec() carefully. Note what mem[] and reg[] are. Pause to
reflect on how simple and cool this all is. This right here is all that a computer needs to do.
Now, you’ll notice two TODO comments in exec(), for the two double-indirect jump
instructions that you implemented in Java in Assignment 7. Implement them again, this time in
C. Use the implementations of the two load instructions and the indirect jump instruction as a
guide.
Test your implementation by creating a small assembly test file. You might want to first test the
test file in the Java version of the simulator. Make sure that your test program changes either
memory or the register file in a recognizable way when the two instructions execute correctly.
Then, convert this file to machine code (see above) and run it in your modified C simulator,
having it print whatever memory or registers you need to confirm correctness (see above). You
might need to add print statements or otherwise debug sm.c.
Replace Switch Statements with Jump Tables [35%]
Finally, to see how the compiler implements switch statements like those found in sm.c, copy
this file to the file sm-jt.c and then modify sm-jt.c to remove all switch statements in the
exec() procedure and replace them with jump tables and goto’s as described in class. Note
that there are two switch statements and so you will need two jump tables.
Label pointers (e.g., &&L0) and double-indirect goto’s (e.g., goto *jt[i]) are gnu-C
extensions and so some compilers may not support them (all versions of gcc and llvm (the
Mac compiler) do support these extension). So, you may need to move to a lab computer to test
this your program.
Now, test your program. Start with simple-test.m. This test uses one instruction from each
of the switch statements and so if it works you’ll likely have got this mostly right. You’ll also
want to use test.m to ensure that you are dispatching to the correct case block for every
instruction. The easiest way to do this is to place a print statement in every case block and then
run the test to ensure that every print statement executes, and the execute in the correct order.
What to Hand In
Use the handin program.
The assignment directory is ~/cs213/a8, it should contain the following plain-text files.
1. PARTNER.txt containing your partner’s CS login id and nothing else (i.e., the 4- or 5-
digit id in the form a0z1). Your partner should not submit anything.
2. For Question 1: list.c and trunc.c.
3. For Question 2: q2.s and q2.c.
4. For Question 3: sm.c and sm-jt.c.

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[SOLVED] Cpsc 213 – assignment 8 dynamic control flow
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