Design a hardwired control unit for the following architecture. Use the structure that you have designed in Part 4 of Project 1.

INSTRUCTION FORMAT

The instructions are stored in memory in little endian order. Since the RAM in Project 1 has 8-bit output, IR cannot be filled in one clock cycle. Fortunately, you have L/H signal in the IR and you can load MSB and LSB separately in two clock cycles:

• In the first clock cycle, LSB of the instruction must be loaded from an address A of the memory to LSB of IR [i.e., IR(7-0)].

• In the second clock cycle, MSB of the instruction must be loaded from an address A+1 of the memory to MSB of IR [i.e., IR(15-8)].

There are two types of instructions as described below.

• Instructions with address reference have the format shown in Figure 1:

• The OPCODE is a 4-bit field (See Table 1 for the definition).

• The next bit [i.e., IR(11)] is unused, you set it as 0

• The ADDRESSING MODE is a 1-bit field (See Table 3 for the definition).

• The REGSEL is a 2-bit field (See left side of Table 2 for the definition).

• The ADDRESS is an 8-bit

Figure 1: Instructions with an address reference

• Instructions without address reference have the format shown in Figure 2:

• The OPCODE is a 4-bit field (See Table 1 for the definition).

• The DESTREG is a 4-bit field which specifies the destination register (See right side of Table 2 for the definition).

• The SRCREG1 is a 4-bit field which specifies the first source register (See right side of Table 2 for the definition).

• The SRCREG2 is a 4-bit field which specifies the second source register (See right side of Table 2 for the definition).

Figure 2: Instructions without an address reference

Table 1: OPCODE field and SYMBols for operations and their descriptions

Table 2: REGSEL (Left) and DESTREG/SRCREG1/SRCREG2 (Right) select the register of

interest for a particular instruction

Table 3: Addressing modes

EXAMPLE

Since PC value is initially 0, your code first executes the instruction in memory address 0x00. This instruction is BRA START_ADDRESS where START_ADDRESS is the starting address of your instructions.

The code given below adds data that are stored at memory addresses 0xA0, 0xA1, 0xA2, 0xA3, and 0xA4 (i.e., calculates total = M[A0] + M[A1] + M[A2] + M[A3] + M[A4]). Then, it stores the total in memory address 0xA6 (i.e., M[A6]). It is written as a loop that iterates 5 times.

You have to determine the binary code of the program and write it to the memory. Your final logisim implementation is expected to fetch the instructions starting from address 0x00, decode them and execute all instructions, one by one.

BRA 0x20 # This instruction is written to the memory address 0x00,

# The first instruction must be written to the address 0x20

LD R1 IM 0x05 # This first instruction is written to the address 0x20,

# R1 is used for iteration number

LD R2 IM 0x00 # R2 is used to store total

LD R3 IM 0xA0

MOV AR R3 # AR is used to track data address: starts from 0xA0