[SOLVED] 函数式编程haskell代写:CO2008, Functional Programming

30 $

File Name: 函数式编程haskell代写:CO2008,_Functional_Programming.zip
File Size: 574.62 KB

SKU: 0000499710 Category: Tags: , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , ,

Or Upload Your Assignment Here:


Worksheets CO2008, Functional Programming 2017, University of Leicester

Worksheet 4: Datatypes

Template file: Labs: Hand-in: Topics:

Worksheet4.hs
Friday 10 and 17 March 2017
21.00 hr on 19 Sunday March 2017
Algebraic and recursive types. Trees, paths and errors.

1. A pack of playing cards contains 52 cards. Each card has a ’value’ which is taken to be an element of the type

data Value = A|Two|Three|Four|Five|Six|Seven|Eight|Nine|Ten|J|Q|K

and it has a ‘suite’ which is taken to be an element of the type

data Suite= Hearts | Spades | Clubs | Diamonds

A card is thus an element of

type Card = (Value, Suite)
  1. (a)  Define a show function for Value that transfers the values into the following strings: ”A”, ”2”, …, ”10”, ”J”, ”Q”, ”K”,
  2. (b)  Define a show function for Suite that transfers the elements of Suite into the strings: ”H”, ”S”, ”C”, ”D”
  3. (c)  (unassessed) Is it possible to write a show function for Card that would transform (A,Heart) into the string AH.
  4. (d)  Give a concise definition of a value pack::[Card] containing all of the possible playing cards in some order. Use list comprehension.
  5. (e)  There are two colours of playing card
     data Colour = Red | Black

    A card is Red if its suite is either Diamonds or Hearts and is Black otherwise. Write a function to determine the colour of a card.

  6. (f)  A common way to shu✏e a pack of cards is to repeatedly split the pack roughly in the middle and then to interleave the two por-

tions. Write a function split::Int->[a]-> Error ([a],[a]) so that split n divides a list in two at the point just after the n-th element (we start counting from n=1). For instance,

1

split 0 [1,2, 3,4,5] = Ok ([], [1,2,3,4,5])
split 2 [1,2, 3,4,5] = Ok ([1,2], [3,4,5])

Give an error in case the number is negative or larger than the length of the list. For instance,

split 8 [1,2, 3,4,5] = Fail

split (-5) [1,2, 3,4,5] = Fail
Write a second function to interleave two lists of type [a], possibly of

di↵erent lengths. For instance, interleaving two list of integers looks like this:

interleave [1,2,3] [4,5,6,7,8,9] = [1,4,2,5,3,6,7,8,9].

(g) A shu✏e of the pack is specified by giving a list of integers. For example, the list standard below corresponds to the shu✏e in which the pack is split after the 23rd card, interleaved, split again after the 26th card, interleaved, and so on.

 standard :: [Int] standard = [23,26,25,31,19,27]

Write a function shuffle which can be used on any list xs to calcu- late the e↵ect of shu✏ing the list according to a list of integers.
Use the functions split and interleave defined in the previous part. Give an error in case split gives an error, i.e. give an error in case there is a number which is negative or larger than the length of the list xs.

2. A binary tree can be used as a database. Here, the leaves of a tree are either ND indicating no data, or Data d where d is a data item.

data Btree a = ND | Data a |Branch (Btree a) (Btree a)

One can give a path to a leaf by giving a list such as [L,R,L] which indicates the leaf one arrives at by moving left, right, left from the root of the tree (of course, there may be no such leaf).

data Dir = L | Rtype Path =[Dir]
  1. (a)  Define extract which given a path and a binary tree, outputs the data at the end of the path, and gives an error value when the path does not match any data.
  2. (b)  Define add, whose three inputs are some data, a path, and a binary tree. The output consists of the binary tree, modified to include the data item at the end of the path. In more detail, if the input path ends in a leaf node of the form ND the tree is extended to contain the new data. If the path leads to a branching node or a leaf node of the form Data d an error value is given.

    2

(c) Suppose the tree holds data of type a. Define the function findpath, which given a function f, some data x and a tree t, returns the lists of paths (possible empty) in t to the nodes of the form Node d where fdis equal tox.

3. Consider the following types:

data Tree a = U | F a (Tree a) (Tree a) deriving Show
type Person = String

We will use instances of this datatype to store genealogical information. Example: the information that Anna has Fer-Jan and Paula as parents will be denoted by

F “Anna” (F “Fer-Jan” U U) (F “Paula” U U).

It is convention that the second argument of F represents information about the father, and the last argument information about the mother. The letter U indicates the absence of information.

  1. (a)  Explain the phrase “deriving Show” in the declaration of Tree. Also explain why there is no need for such a phrase in the declaration of Person.
  2. (b)  What is the type of the function putString? Explain briefly the e↵ect of the term putStr “Hello”.
  3. (c)  For later use in this question: write down your favourite parametri- cally polymorphic function
    sort :: Eq a => (a -> a -> Bool) -> [a] -> [a]
    that given a strict order relation ord and a given list xs, sorts xs using ord.

    Example: sort < [3,2,1] = [1,2,3]

  4. (d)  In genealogy people occurring in a family tree are often labelled with a number, as follows: people at the root of the tree get number 1. Next we apply the rule that, if people have number n then his/her father will get number 2*n and his/her mother will get number 2*n+1, until all people in the tree have been labelled.

    Write down a function genlabel :: Tree a -> Tree (Int,a) that adds a number to the elements of a tree following the above practice. Example: genlabel (F “Fer-Jan” (F “Willem” U (F “Adriana”
    U U)) U) = F (1,”Fer-Jan”) (F (2,”Willem”) U (F (5,”Adriana”) U U)) U .

Larger terms in this F,U notation are pretty much unreadable. The family tree of Anna that includes her grandparents would look like:

F "Anna" (F "Fer-Jan" (F "Willem" U U) (F "Nettie" U U)) (F "Paula"(F "Mario" U U) (F "Martha" U U))

Genealogists have invented all sort of ways to print such terms either as lists as 2-dimensional trees.

3

(e) We want to print the above family tree of Anna as a list, using the genealogical labelling of the previous item:

 1:Anna 2:Fer-Jan 3:Paula 4:Willem 6:Mario 7:Martha 9:Adriana

Write a function printlist :: Tree Person -> IO() that takes a tree of type Tree Person and produces a list of labelled names, ordered by the genealogical label and printed as the above example, each label name of the form n: name on its own line.

Hint: given a tree, add genealogical labels to the tree, flatten the tree to a list of pairs of type (Int,Person) and then pretty print the list as indicated by the above example: each pair on its own line.

To finish, we want to print the above family tree of Anna as a 2D-tree as follows:

 Willem Fer-Jan

Nettie

Anna

In this format the information of a person is printed between the lines of the information of his/her parents, in so far as there is information of them given. The indentation is produced with tab characters. If a person has k generations distance from the root of the tree, then we use k tab characters for indentation.

The above tree was the result of printing the following string:

“ttWillem
tFer-Jan
ttNettie
Anna
ttMario
tPaula
ttMartha

(f) Writeafunctionprint2Dtree::TreePerson->IO()thattakes a tree of type Tree Person and produces a family tree as above. Hint: one possibility is to proceed more or less as in the previous item. But take care that you print the names in the proper order: children between their parents. Change the pretty printing, so that the pairs pretty-print as indicated by the above example: each pair (n, person) will be decoded in a string of characters beginning with a suitable number of tab characters.

4

Mario Paula

Martha

Reviews

There are no reviews yet.

Only logged in customers who have purchased this product may leave a review.

Shopping Cart
[SOLVED] 函数式编程haskell代写:CO2008, Functional Programming
30 $