MIPS
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[SOLVED] 程序代写代做代考 algorithm The Red/Blue computation simulates two interactive flows: an n by n board is initialized so cells have one of three colors: red, white, and blue, where white is empty, red moves right, and blue moves down. (The board may be initialized with roughly 1/3 cells in read, 1/3 in white and 1/3 in blue and colors should be interleaved and spread across the board. You need to write a separate function board_init to initialize the board.) In the first half step of an iteration, any red color can move right one cell if the cell to the right is unoccupied (white); on the second half step, any blue color can move down one cell if the cell below it is unoccupied (white); the case where red vacates a cell (first half) and blue moves into it (second half) is okay. Colors wraparound to the opposite side when reaching the edge. Viewing the board as overlaid with a t by t grid of tiles (for simplicity t divides n, i.e., every tile contains n/t by n/t cells), the computation terminates if any tile’s colored cells are more than c% one color (blue or red).
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