[Solved] COEN79-Lab 6 Sequence class (using linked list)

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In this project, first complete the implementation of linked list toolkit functions. Then complete the implementation of the sequence class. Please note that we do not use all of these functions for the implementation of the sequence class. For example, list_remove_dups() and list_detect_loop() are not used by the sequence class. You can use node_test.cpp to test the operation of toolkit functions.

The sequence class stores items in a forward linked list, in their sequence order. The current item on the list can be maintained by a member variable that points to the node that contains the current item. When the start function is activated, we set this current pointer to point to the first node of the linked list. When advance is activated, we move the current pointer to the next node on the linked list.

We propose five private member variables for the new sequence class. The first variable, many_nodes, keeps track of the number of nodes in the list. The other four member variables are node pointers:

  • head_ptr and tail_ptr: The head and tail pointers of the linked list. If the sequence has no items, then these pointers are both NULL. The reason for the tail pointer is the attach Normally this function adds a new item immediately after the current node. But if there is no current node, then attach places its new item at the tail of the list, so it makes sense to keep a tail pointer around.
  • cursor: Points to the node with the current item (or NULL if there is no current item).
  • precursor: Points to the node before current item (or NULL if there is no current item or if the current item is the first node). Can you figure out why we propose a precursor? The answer is the insert function, which normally adds a new item immediately before the current node. But the linked-list functions have no way of inserting a new node before a specified node. We can only add new nodes after a specified node. Therefore, the insert function will work by adding the new item after the precursor node, which is also just before the cursor

Keep in mind the four rules for a class that uses dynamic memory:

  • Some of your member variables are pointers. In fact, for your sequence class, four member variables are pointers.
  • Member functions allocate and release memory as needed. Dont forget to write documentation indicating which member functions allocate dynamic memory so that experienced programmers can deal with failures.
  • You must override the automatic copy constructor and the automatic assignment operator. Otherwise two different sequences end up with pointers to the same linked list.
  • The class requires a destructor, which is responsible for returning all dynamic memory

to the heap.

The value semantics of your new sequence class consists of a copy constructor and an assignment operator.

The primary job of both these functions is to make one sequence equal to a new copy of another. The sequence that you are copying is called the source, and we suggest that you handle the copying in these cases:

  1. If the source sequence has no current item, then simply copy the sources linked list with Then set both precursor and cursor to the null pointer.
  2. If the current item of the source sequence is its first item, then copy the sources linked list with Then set precursor to NULL, and set cursor to point to the head node of the newly created linked list.
  3. If the current item of the source sequence is after its first item, then copy the sources linked list in two pieces using list_piece. The first piece that you copy goes from the head pointer to the precursor; the second piece goes from the cursor to the tail pointer. Put these two pieces together by making the link field of the precursor node point to the cursor node. The reason for copying in two separate pieces is to easily set the precursor and cursor.

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[Solved] COEN79-Lab 6 Sequence class (using linked list)
$25