[Solved] Strings and File I/O ISTA 130 Hw6

5/5 – (4 votes)

Introduction. This homework is intended to give you practice with string indexing, slicing, and methods, and file I/O and traversing files by line.

Instructions. Create a module named strings.py. Below is the spec for six functions. Implement them and upload your module to the Hw6 D2L Assignments folder.

Testing. Downloadtest_strings.pyandputitinthesamefolderasyourstrings.pymodule and the auxiliary testing files. Run it from the command line to see your current correctness score. Each of the six functions is worth 16.7% of your correctness score. You can examine the test module in a text editor to understand better what your code should do. The test module is part of the spec. The test file we will use to grade your program may be different but if your code passes the one provided, it will pass the one we use.

Documentation. Your module must contain a header docstring containing your name, your section leaders name, the date, ISTA 130 Hw6, and a brief summary of the module. Each function must contain a docstring. Each function docstring should include a description of the functions purpose, the name, type, and purpose of each parameter, and the type and meaning of the functions return value.

Grading. Your module will be graded on correctness, documentation, and coding style. Code should be clear and concise. You will only lose style points if your code is a real mess. Include inline comments to explain tricky lines and summarize sections of code (not necessary on this assignment).

Collaboration. Collaboration is allowed. You are responsible for your learning. Depending too much on others will hurt you on the tests. Helping others too much harms them in reality. Cite any sources/collaborators in your header docstring. Leaving this out is dishonest.

Resources.

https://docs.python.org/3.7/tutorial/index.htmlString methods: https://docs.python.org/3.7/library/stdtypes.html#string-methods The standard library: https://docs.python.org/3.7/library/index.htmlBuilt-in functions: https://docs.python.org/3.7/library/functions.html

If you dont have this document with you and you want to find, say, all string methods, you can start the interpreter and type dir(str) or pass a string variable to the built-in function dir. You will get a list of all of the string methods you might be interested in and then some. Here are the ones that count:

capitalizecasefoldcentercountencodeendswithexpandtabs

isidentifierislowerisnumericisprintableisspaceistitleisupper

rindexrjustrpartitionrsplitrstripsplitsplitlines

findformatformat_mapindexisalnumisalphaisdecimalisdigit

joinljustlowerlstripmaketranspartitionreplacerfind

startswithstripswapcasetitletranslateupperzfill

If you want more information on, say, islower, type help(str.islower) into the interpreter. This functionality is available for any type.

Function specifications.

Prior note:

US_to_EU: This function takes a string representing a US style date and returns a European style date string (if it takes an argument, it must have a corresponding parameter). US strings have the month first, European strings have the day first. US uses slashes as separators, Europe uses dots. Example calls:

     US_to_EU('3/13/18')  -->  '13.3.18'     US_to_EU('3/13/2018')  -->  '13.3.2018'     US_to_EU('03/13/2018')  -->  '13.03.2018'

To prepare for this function, open a shell and enter the following code:

     date = '3/13/18'     num_lst = date.split('/')     num_lst     num_lst[0]

This is not code that is meant to be cut-and-paste into your file. It should teach you what you need to know to solve the problem as described it is not itself a solution.

is_phone_num: ThisBooleanfunctiontakesastringandreturnsTrueifitisintheformatddd- ddd-dddd,wheredisadigit,Falseotherwise. Examplecalls:

     is_phone_num('123-456-7890')  -->  True     is_phone_num('123-4556-7890')  -->  False     is_phone_num('(123)456-7890')  -->  False

To prepare for this function, open a shell and enter the following code:

     possible_num = '123-456-7890'     num_lst = possible_num.split('-')

If your code opens an input file in write mode, it will destroy the file and you will need to

re-download it. The three files that might potentially be destroyed

are redact_in.txt, highlight_in.txt, and plagiarism_in.txt, so those functions can

fail even if the code is correct if previous versions of the code have destroyed the test files.

     num_lst     len(num_lst)     len(num_lst[0])     num_lst[0].isdigit()

redact_line: This function takes a string and returns a new string that has all of the phone numbers (as defined in the previous function description) in the original string replaced by XXX-XXX-XXXX. Assume that the argument ends in a newline. Phone numbers are bracketed by spaces, newlines, and/or the beginning of the string. You will need to use slicing with or without the replace method becausereplacealwaysstartssearchingfromthestartofthestring. Therefore,replacealonewill not be enough (and is not actually necessary). split and join will also not be helpful.

redact_line(123-456-7890
) > XXX-XXX-XXXX
redact_line(123-456-7890 123-456-78901 123-456-7890
) >

XXX-XXX-XXXX 123-456-78901 XXX-XXX-XXXX

This one is hard, so heres a restatement of the problem, with more implementation suggestions: you need a loop to traverse the string. Make the limit of your for loop len(s) 12. This will make it easier. There are three requirements for having found a phone number. On the left, it must be the beginning of the line or the character prior to the potential number must be a space. The potential number (a substring of length 12) must return True when passed to the is_phone_number function. Finally, the character after the potential number must be a space or a newline. Once you check for that, you need to redact the number if all of those conditions were True. As stated above, youcantusereplace. Youwillneed:

line = slice up to number + XXX-XXX-XXXX + slice after number

If you like a challenge, try this yourself. But heres the entire solution (which wont work until is_phone_num works):

def redact_line(line):    # can't use replace only because it always starts at 0    for i in range(len(line) - 12):

if ((i == 0 or line[i 1] == ) andline[i + 12] in
and is_phone_num(line[i:i + 12])):

line = line[:i] + line[i:].replace(line[i:i + 12], XXX- XXX-XXXX, 1)

return line

redact_file: This function takes a string filename. It writes a new file that has the same contents as the argument, except that all of the phone numbers are redacted. Assume that the filename has only one period in it. The new filename is the same as the original with _redacted added before the period. For instance, if the input filename were myfile.txt, the output filename would be myfile_redacted.txt. Make sure you close your output file.

The first hard task in this function is to make the output filename from the input filename that was passed in. You can break it into two pieces by splitting on the dot or by using the index method and slicing. Then put it back together again using string concatenation.

We are also working with files in this one. To open a file with a filename stored in the variable fname, in read mode use the open function as such: fp = open(fname). You will need to open the output file in write mode: open(fname, w). Then you can traverse the input file line-by-line with this syntax: for line in fp:. To write to an output file, use the write method: fp_out.write(line).

plagiarism: This Boolean function takes two filenames. If any line occurs in both files, return True. If not, return False. I suggest using nested loops. With nested loops, we call the loop that is in the body of the other loop, the inner loop. The loop that contains the inner loop is the outer loop. Open the second file inside the outer loop:

    for line1 in file1:        file2 = open(fname2)        for line2 in file2:

Python only lets you read the file once per open, so you need this order of instructions. Make sure your return False is outside of both loops. Otherwise, you will only compare the first two lines of the files. Make sure you close the file that gets read repeatedly after the inner loop but still inside the outer loop.