[Solved] SOLVED: Date class solution

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Lab Overview This lab investigates Python classes and their use. The particular focus is a Date class. Please download Date.py from the Laboratories heading of the Piazza resource page. Please also download Point2d.py from the Lectures heading. This is the solution from Lecture 17, with additional explanatory comments. Please continually refer to this example when working on the lab. Start by looking Date.py: You will notice two global variables at the start: one is a list of the number of days in each month, and the second is a list giving the names of each month. These are used here as constants that should not be changed. We will get to them in Checkpoint 2. The Date class does not have anything in it and is therefore non-functioning. Your job will be to replace the pass with methods and attributes. The testing code is in the main code area. This will not work until you add methods. Checkpoint 1 The dates will be stored with three attributes: the year, the month, and the day of the month, all as integers. These attributes will be created / assigned in the initializer methods. Therefore, please implement the following methods for the Date class __init__: This should take a year, a month and a day with default values of 1900, 1, 1. d1 = Date(1972, 3, 27) d2 = Date(1998) # Will be January 1, 1998 __str__: Format the data as a string with year/month/day. For example, d1 = Date(1972, 3, 27) s = str(d1) s 1972/03/27 s1 = Date(1983, 11, 2) print s1 1983/11/02 The example in Point2d.py is especially important here. As a hint for how to insert the 0 before the 3 in 03, you must make use of the rjust method of strings. For example, s = 5 s1 = s.rjust(2,0) print s1 05 s = 21 s1 = s.rjust(2,0) print s1 21 In the call to rjust, the 2 is the number of spaces, and the 0 is the character to inserted when there arent enough characters in the string to be printed. same_day_in_year: This should determine if two dates are on the same day within a year, even if they are not within the same year. For example, given d1 = Date(1972, 3, 27) d2 = Date(1998, 4, 13) d3 = Date(1996, 4, 13) d1.same_day_in_year(d2) False d2.same_day_in_year(d3) True There is already code in the main area of Date.py to partially test these. The test code does not include code for testing the default assignments so you should add that. It also does not test all of the cases, so you will need to add some of your own. To complete Checkpoint 1: show your code and the result of running it to a lab TA or a mentor. Checkpoint 2 Date Class Methods Continuing with the Date class, please implement and test the following two methods, each of which involves signicantly more logic that the rst three methods. is_leap_year: This should return true if the year is a leap year. Leap years occur when the year is divisible by 4. The exception to this rule is years that are divisible by 100 but not 400. Got it? In other words, 2000, 2004, 2008 and 2012 were all leap years, but 1900, 2002, and 2011 were not. As examples, using the above values of d1 and d2 d1.is_leap_year() True d2.is_leap_year() False __lt__: This is the less than operator and it should return true if the rst Date is earlier than the second. 2 d1 = Date(1972, 3, 27) d2 = Date(1998, 4, 13) d3 = Date(1998, 5, 13) d4 = Date(1998, 4, 11) d1 < d2 True d2 < d3 True d3 < d4 False Observe that there is a great deal more functionality that we could (and should) add to the Date class to make it fully functional, but these functions are enough for now. To complete Checkpoint 2: Add code to test your new functions to the main code of Date.py. Show your code and the test results to a TA or a mentor. Your testing code should show Date objects and function call outputs that test the dierent conditions that each method has to handle. The example calls above cover some but not all of these conditions. Checkpoint 3 Birthdays Create a new .py le for Checkpoint 3 that starts with the line from Date import * This will allow you to use the Date class without having to write something like d = Date.Date() which is what you would have to do if you just imported Date. Instead, you can simply write: d = Date() Start by writing a function that reads birthdays from a le (birthdays.txt is the test le we have provided) and returns a list of Date objects. Then write main function code that scans through this list to nd and output: the earliest birthday corresponding to the person who would be the oldest person represented in the le, the latest birthday corresponding to the youngest person represented in the le, and the name of the month that has the most birthdays. Use the month_names list in Date.py To complete Checkpoint 3: Show a TA or Mentor your code and output. Additional challenges (no extra credit) Implement and test a function called julian_day that returns an integer giving the Julian day corresponding to the current date. The Julian day is the numbered day within the year, with January 1 being Julian day 1, February 1 being Julian day 32, February 28 being Julian day 59, and March 1 being Julian day 60 or 61, depending on whether or not it is a leap year. This method should make use of the days_in_month list. Here are examples of using the method d1 = Date(1972, 3, 27) d2 = Date(1998, 4, 13) d1.julian_day() 87 d2.julian_day() 103 You must make use of is_leap_year in your julian_day function.

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[Solved] SOLVED: Date class solution
$25