[Solved] CptS 122 Assignment #4

This assignment is a continuation of lab 7. In this homework, you will create a program that will add simple effects to a PPM image.PrerequisitesBefore beginning this assignment, you will need some sort of imaging software that can open PPM-based images. I recommend Ifranview for Windows as its free and lightweight.PPM Image FormatThe PPM image format is encoded in human-readable ASCII text. It might be helpful to read over the formal PPM specification document. A PPM document has two pieces: the header and the body. The header is always the top three uncommented lines in the file:P34 4255The first line specifies the type of image that is contained within the file. We will always use the P3 specification. The second line specifies the number of columns and rows present in the image. In this example, we have a 44 image. The final number indicates the maximum value for each red, green, and blue element in the picture. Having a max value of 255 is quite common and is the value that we will always use. Below the header is the body of the PPM file. Each pixel has a red, green, and blue value. For example, the content of our 44 image might be:0 0 0 100 0 0 0 0 0 255 0 2550 0 0 0 255 175 0 0 0 0 0 00 0 0 0 0 0 0 15 175 0 0 0255 0 255 0 0 0 0 0 0 255 255 255With these values, the pixel in the first column and row has a RGB value of (0,0,0) and the last column in the first row has an RGB value of (255,0,255). A blown-up image containing these values would look like:TaskYour task is to write a program that will perform the following basic image manipulations on a user-specified image. Below is a reference value and the images that result from the image processing.Original ImageRemove RedWill remove all red (i.e. set red to 0) pixels in the imageRemove GreenWill remove all green pixels in the imageRemove BlueWill remove all blue pixels in the imageNegate RedWill negate all red pixels in an image. To negate a color, simply subtract the current pixels red color value from 255.Negate GreenWill negate all green pixels in an image.Negate BlueWill negate all blue pixels in an image.Add Random NoiseWill add random noise to the image by randomly selecting a value ranging from -10 to 10 and adding that value to the pixels current value. If the addition causes the pixel value to be less than 0, then set to 0. Likewise, if the addition causes the pixels value to be greater than 255, just set the pixels value to 255. For example, we randomly generate the number -7. Next, we add -7 to each of the current pixels red, green, and blue values.High ContrastExamine each color in a pixel. If the color is greater than half of 255, then max the color out (i.e. set to 255). Otherwise, set the value to 0. For example, performing a high contrast operation on a pixel whose RGB values are 170, 50, 100 would result in an RGB value of 255, 0, 0.GrayscaleConverts the image to grayscale by setting the value of each color in a given pixel to the average of all three values. For example, if a pixels RGB was 177, 15, 39, the resulting RGB value would be 77, 77, 77.BONUS Flip HorizontalFlips the image along the horizontal axis.BONUS Flip VerticalFlips the image along the vertical axis.Chaining Effects TogetherNote that manipulations can be chained together. Below is the image generated from performing a negate red, negate green, and negate blue operation.UML DiagramIn order to complete this assignment, you must develop the following classes:Note that it might help to zoom in on the UML diagram. Basically, we have our Point class that we developed in Lab 7. In the center, we have the SimpleImageEffect interface that defines a single pure virtual function called processImage. Each effect described in the previous section derives itself from SimpleImageEffect, implementing the processImage method in such a way to fulfill its role (e.g. NegateRedEffect will negate all red pixels in the image). Note that while a factory-type class isnt defined, it may be useful for you to write one.Also note the white diamond going from SimpleImageEffect to Point. This is called aggregation and is another form of a has-a relationship. The main difference between aggregation and composition (black diamond) has to deal with the lifespan of an object. A black diamond means that the object goes out of scope at the same time as the owner class. A white diamond means that the object stays alive even when the owner class goes out of scope. If you think about the lifespan of a Point, it is easy to see that a given Point will exist for a longer period than the SimpleImageEffect. This makes sense as the Point still needs to be written to the output file!Sample OutputBelow is the sample output from my program:Note that the program allows for unlimited effects to be added to a given image. Also note that some of these effects might take a while for your computer to process!Header Comment, and Formatting1. Be sure to modify the file header comment at the top of your script to indicate your name, student ID, completion time, and the names of any individuals that you collaborated with on the assignment.2. Remember to follow the basic coding style guide. A basic list of rules can be found on OSBLE.DeliverablesYou must upload your program store through OSBIDE no later than midnight on Friday, March 14, 2014. For more information on how to submit an assignment, read this page.Grading CriteriaYour assignment will be judged by the following criteria:Error Free Compile (weight: 5%) [0] Your program contains compiler errors. [1] Your program compiles without issue.Error Free Runtime (weight: 10%) [0] Your program throws a runtime exception. [1] Your program does not encounter any runtime exceptions.Pointer Cleanup (weight: 5%) [0] Your program does not delete any dynamically-created pointers [1] Your program remembers to delete some, but not all dynamically-created pointers [2] Your program deletes all dynamically-created pointersStyle (weight: 5%) [0] Your program does not contain good style. Variables are poorly named, your program doesnt contain a header, there is little or no documentation, your document isnt properly formatted (indentation, whitespace, etc.), and is generally hard to read. [1] Your program contains okay style. Some of the items listed in the [0] section are accounted for [2] Your program contains great style. Almost everything in listed in the [0] section is accounted for.User Interface (weight: 10%) [0] Your program does not even attempt to follow the UI guidelines [1] Your programs UI has major inconsistencies when compared to the sample output [2] Your programs UI has minor inconsistencies when compared to the sample output [3] Your program completely matches the specified user interface guidelinesClass Correctness (weight: 15%) [0] Your program does not contain nor use any of the classes specified in the UML diagram [1] Your program contains but does not use the classes specified in the UML diagram [2] Your program contains and partially uses the classes specified in the UML diagram [3] Your program contains and uses the classes specified in the UML diagram.Required Functionality (weight: 5% / ea) Remove red Remove green Remove blue Negate red Negate green Negate blue Add random noise High contrast GrayscaleCompound Operations (5%) [0] Your program does not allow for compound image manipulations (i.e. cannot combine multiple image manipulations in a single program run) [1] Your program allows for compound image manipulations, but does not perform them correctly (i.e. things dont output as they should) [2] Your program allows for compound image manipulations and performs them correctly.EXTRA CREDIT (5%) [0] You do not attempt the extra credit [1] You add either the ability to flip the image horizontally or vertically. [2] You add the ability to flip the image both horizontally and vertically.